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kolezko [41]
3 years ago
13

Please help me solve this fractions. (show your work)​

Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

23: 21\frac{23}{55}  25: 1\frac{44}{45}

Step-by-step explanation:

<u>Question 23</u>:

1) add the whole numbers together: 15+5=20

2)To add fractions, both need to have the same denominator. Find a number that is a multiple of both denominators (in this case 55)

\frac{9}{11} → \frac{45}{55} (multiply the numerator and denominator by 5)

\frac{3}{5} → \frac{33}{55} (multiply the numerator and denominator by 11)

3) add the fractions together

\frac{45}{55} + \frac{33}{55} = \frac{78}{55} (add the numerators)

4) Turn the improper fraction into a mixed number

Divide 78 by 55. You'll get a whole number and a remainder. The remainder is the new numerator: In this case 55 enters 78 once with a remainder of 23. Therefore:

1\frac{23}{55}

5) Add the whole numbers together to get the final answer:

20+1= 21

Answer: 21\frac{23}{55}

<u>Question 25</u>:

Follow the above steps but subtract instead of adding

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<em><u>Solution:</u></em>

<em><u>The slope intercept form of equation is given as:</u></em>

y = mx + c ------ eqn 1

Where,

m is the slope of line

c is the y intercept

From given,

slope = m = 3

y intercept = c = 5

<em><u>Substitute m = 3 and c = 5 in eqn 1</u></em>

y = 3x + 5

3x - y = -5

Thus the equation of line is found

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Y= -2x+ 4
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Read 2 more answers
The first two terms of a sequence are a1 =4 and a2= -2. Let a3 be the third term when the sequence is arithmetic and let b3 be t
stepan [7]

Answer:

a3 + b3 = -7

Step-by-step explanation:

When the sequence is A.P

a1 =4 and a2= -2

Common difference,d = a2 - a1

= -2 - 4

d = -6

a3 = third term

a3 = a1 + 2d

= 4 + 2(-6)

= 4 - 12

= -8

a3 = -8

When the sequence is geometric

a1 =4 and a2= -2

Common ratio, r = a2/a1

= -2/4

r = -1/2

Or

r = -0.5

b3 = third term

b3 = ar²

= 4 * (-1/2)²

= 4 * 1/4

= 4/4

= 1

b3 = 1

a3 + b3 = -8 + 1

= -7

a3 + b3 = -7

8 0
3 years ago
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