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Katen [24]
3 years ago
7

Does anyone know this answer ?

Mathematics
2 answers:
Arturiano [62]3 years ago
4 0

Answer:

10z + 5

Step-by-step explanation:

NeTakaya3 years ago
4 0
If I’m not mistaken I think is the first one

10z + 5
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What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
Read 2 more answers
Solve for x round to the nearest tenth<br>​
alisha [4.7K]

Answer:

13.7

Step-by-step explanation:

a^2+b^2=c^2. 9.2^2 +x=16.5^2 x=16.5^2-9.2^2. x=root187.61 which is 13.7.

Hope this helps plz mark brainliest :D

5 0
3 years ago
I need help ASAP please and thank you
Leokris [45]
Y= 0.5x - 1
It might be written as half x like 1/2
8 0
3 years ago
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Solve the equation. -5/4n =40
lina2011 [118]
I think the answer is a
8 0
4 years ago
I need help I don't understand how to do this
murzikaleks [220]
What is the problem? Is there isn't a problem, do you just what help for a test?
6 0
4 years ago
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