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Oksi-84 [34.3K]
3 years ago
12

What are the x-intercepts for x2 - 5x + 6 = 0? (hint: factor first)

Mathematics
1 answer:
wlad13 [49]3 years ago
6 0

Answer:x-intercepts (0,2) ; (0,3)

Step-by-step explanation:

x^2 - 5x + 6 =0

(x-2)(x-3) = 0            

[-2 and -3 was the factors of 6, which make them equal to -5 when them add].

x-2=0            x-3=0

   x=2               x=3

so x-intercepts (0,2) ; (0,3)

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You're told that S_{16}=-288 (the sum of the first 16 terms in the sequence, presumably). Well, we know that

S_{16}=\displaystyle\sum_{n=1}^{16}a_n=\sum_{n=1}^{16}(-21+(n-1)d)
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