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sesenic [268]
3 years ago
13

A bag with 6 marbles is shown below. (3 marbles are red, 1 is yellow, and 2 are blue.) A marble is chosen from the bag at random

. What is the
probability that it is red?
Write your answer as a fraction or a whole number.

Mathematics
2 answers:
Contact [7]3 years ago
8 0
Not simplified: 3/6 simplified: 1/2
11Alexandr11 [23.1K]3 years ago
5 0

Answer:The answer is 1/2 or you can do 3/6 if it doesnt need to be simplified

Step-by-step explanation:

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In a wood there are 420 silver birch trees 160 oak trees and 300 wild cherry trees what percentage is the oak trees give answer
frosja888 [35]
That would be 7.2 if my calculations are correct
6 0
4 years ago
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12 subtracted from a negative number is 16. Write as an equation
cupoosta [38]

Step-by-step explanation:

(-x)-12=16

-x=28

x=28

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7 0
3 years ago
15 DVDs, 1/5 were documentaries. How many of the movies were documentaries
Maksim231197 [3]

Answer:

3 of the DVDs were documentaries.

Step-by-step explanation:

We know that at first, there were 15 DVDs in total.

Now, we need to find how much 1/5 of 15 DVDs were equal to.

1/5 of 15 is equal to the number 3.

So, that means our answer is 3 of the DVDs are documentaries.

Hope this helps.

3 0
3 years ago
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A right triangle has a hypotenuse of 70 feet and a leg of 35 feet. What is the length of the other leg? Select one:
saveliy_v [14]
H = 70ft.
P = 35ft.
B = ?

H^2 = P^2 + B^2
70×70 = (35×35) + B^2
B^2 = 4900-1225
B = √3675
B = 35√3 ft.
3 0
4 years ago
Use the diagram below to answer the question.
Lunna [17]

Answer:

The length of shadow is 69 foot.

Step-by-step explanation:

We are given a shadow of lighthouse.

Length of top of lighthouse to end of shadow is 90 ft.

Angle make at top of lighthouse is 50°

Distance from foot of lighthouse to end of shadow is x ft.

we need to find the length of shadow i,e x ft

Using trigonometry ration:

\sin\theta=\dfrac{P}{H}

\sin50^\circ=\dfrac{x}{90}

x=90\times 0.766

x=68.94\approx 69\text{ ft}

Hence, The length of shadow is 69 foot.

7 0
3 years ago
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