6/8 *3/2.
6*3=18. /8*2=16
18/16
Divide top and bottom by 2
9/8
The answer is going to be c because 12-35=23 and since there is variables you have to add the variable.
Answer:
a. Assume that the population has a normal distribution.
b. The 90% confidence interval of the mean sale time for all homes in the neighborhood is between 219.31 days and 240.69 days.
Step-by-step explanation:
Question a:
We have to assume normality.
Question b:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 1.645.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 230 - 10.69 = 219.31 days.
The upper end of the interval is the sample mean added to M. So it is 230 + 10.69 = 240.69 days.
The 90% confidence interval of the mean sale time for all homes in the neighborhood is between 219.31 days and 240.69 days.
Answer: 10√3 / 3
Step-by-step explanation:
cos 30 = 5 / x
x = 5 / cos 30
= 5 / √3 / 2
= 10 √3
= 10√3 / 3