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2 years ago

Find the solution to the following system of linear

Mathematics

1 answer:

mrs_skeptik [129]2 years ago

8 0

Step-by-step explanation:

$y = 4x - 4 \\ x + y = 11 \\ x + 4x - 4 = 11 \\ 5x = 15 \\ x = 3 \\ y = 4 \times 3 - 4 \\ y = 8$

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1. What is the radius (1 Point) 11 cm

mr_godi [17]

Given that we need to determine the radius of the circle.

Radius:

By definition of radius of circle, the radius is the length of the line which is drawn from the center of the circle to any point on the circle.

From the figure, we need to determine the radius of the circle.

As, we can see that, the distance from the center of the circle to the point on the circle is 11 cm.

Since, we know that, the radius is the distance from the center of the circle to the point on the circle then, the radius of the given circle is 11 cm

Thus, radius of the circle is 11 cm.

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3 years ago

The hockey team won 63 out of the 84 games it played this year.what percent of the games did the team win

Deffense [45]

63 is 75% of 84.
Percent of a Total

3 0

3 years ago

A barn silo, excluding the top, is a cylinder. The silo is 7 m in

Elenna [48]

The volume of the silo is 461.81 m³

Step-by-step explanation:

A barn silo, excluding the top, is a cylinder

The silo is 7 m in diameter
Its height is 12 m

We need to find the volume of the silo

∵ The silo is shaped a cylinder

∵ The volume of a cylinder = base area × height

∵ The base is shaped a circle

∵ Area a circle = π r², where r is the radius of the circle

∴ The volume of the silo = π r² × h

∵ The diameter of the silo = 7 m

∵ The radius of a circle is half the diameter

∴ The radius of the silo = $\frac{1}{2}$ × 7 = 3.5 m

∵ The height of the silo = 12 m

- Substitute the values of r and h in the rule of volume

∴ The volume of the silo = π (3.5)² × 12

∴ The volume of the silo = 147 π = 461.81 m³

The volume of the silo is 461.81 m³

Learn more:

You can learn more about the volume in brainly.com/question/6443737

#LearnwithBrainly

7 0

3 years ago

20points Which represents the restrictions on the radical inequality

Aloiza [94]

The second i think you did good

3 0

2 years ago

Read 2 more answers

Factor f(x)=x4-x3-7x2+13x-6 completely. Then Sketch the graph

Dennis_Churaev [7]

ANSWER TO QUESTION 1

$f(x)=(x-2)(x+3)(x-1)^2$ .

EXPLANATION

The function given to us is,

$f(x)=x^4-x^3-7x^2+13x-6$

According to rational roots theorem,

$\pm1,\pm2,\pm3,\pm6$ are possible rational zeros of

$f(x)=x^4-x^3-7x^2+13x-6$ .

We find out that,

$f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6$

$f(-3)=81+27-63-39-6$

$f(-3)=6-6$

$f(-3)=0$

Also

$f(2)=(2)^4-(2)^3-7(2)^2+13(2)-6$

$f(2)=16-8-28+26-6$

$f(2)=6-6$

$f(2)=0$

This implies that

$x-2 and x+3$ are factors of

$f(x)=x^4-x^3-7x^2+13x-6$ and hence $(x-2)(x+3)=x^2+x-6$ is also a factor.

We perform the long division as shown in the diagram.

Hence,

$f(x)=(x-2)(x+3)(x-1)^2$ .

ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots

$x=2$ and $x=-3$ have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.

Also the root $x=1$ has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.

Now we determine the position of the graph on the following intervals,

$x\le -3$

$f(-4)=(-4)^4-(-4)^3-7(-4)^2+13(-4)-6$

$f(-4)=150\:>0$

$-3\le x \le 1$

$f(0)=-6\:$

$1\le x\le 2$

$f(1.5)=-0.56\:$

$x \ge 2$

$f(3)=24\:>0$

We can now use these information to sketch the function as shown in diagram

4 0

3 years ago