<h3>Answer:</h3>
There are 40,320 ways, in which 8 books can be arranged on a shelf.
<h3>Solution:</h3>
Here, we are to find the number of ways in which 8 books can be arranged on a shelf. The total number of books is 8 and the way of arranging books is also 8.
- If one book is placed in the first place, then 7 books will be placed in front of it. If 2 books are placed in the 2nd place, then only 6 books can be placed after that book. This sequence will continue till 1 .
<u>Permutations </u><u>:</u>
- A permutation is an arrangement of objects in a definite order.
➲<u> P ( n, r )= n ! / ( n - r ) !</u>
- n = total number of objects
- r = number of objects selected
The number of ways to arrange 8 books on a shelf will be :
➝ P ( n, r ) = n ! / ( n - r ) !
➝ P ( n, r ) = 8 ! / ( 8 - 8 ) !
➝ P ( n, r ) = 8 ! / 0 !
➝ P ( n, r ) = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 / 1
➝ P ( n, r ) = 40, 320
ㅤㅤㅤㅤㅤㅤ~ Hence, there are <u>40,320 ways</u> in which 8 books can be arranged on a shelf !
Answer:
There is no option in the question given.
However, In logic and probability theory, two events are mutually exclusive or disjoint if they cannot both occur at the same time. A clear example is the set of outcomes of a single coin toss, which can result in either heads or tails, but not both.
Answer:
3/4.8/5 s your answer... that is option H
360 degrees is a full turn, so if you multiply 30 degreed by 12, you go around in a circle.
Answer:
ok so regrouping is when the top number of a equation is like for EXAMPLE 3 minus 6 ok so 3 is lower than six so the number on the left side you cross that out and you add it to the number that was on top which would make it 13 in this case so 13 minus six is 7 and that’s regrouping
Step-by-step explanation:
