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3 years ago

Please help me can u explain how to do this

Mathematics

2 answers:

Ghella [55]3 years ago

7 0

Answer:

x=41

Step-by-step explanation:

so since this is a right triangle you can use the Pythagorean Theorem to find the missing side. the two sides you know are 'a' and 'b' and the missing side is 'c'. the theorem says that:

a^2+b^2=c^2

so:

9^2 +40^2=c^2

solve for the exponents:

81 +1600=c^2

1681=c^2

and now, since 1681 is the missing side's length squared, we must find the square root of 1681, which is 41

hope this helps :)

iren2701 [21]3 years ago

3 0

And I’m just here to add onto what LoveHannahXO said earlier. You might not need this, but just in case, that “^2” thingy was the square because you can’t do a small 2 on mobile

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|(2,9) J (79) 00 - H(25)

elena-14-01-66 [18.8K]

Answer:

what :(

Step-by-step explanation:

8 0

3 years ago

If the sum of $1! + 2! + 3! + \cdots + 49! + 50!$ is divided by $15$, what is the remainder?

kompoz [17]

Answer:

Step-by-step explanation:

All factorials 5 and above are evenly divisible by 15, so have no remainder. Thus, you are interested in ...

mod(1! +2! +3! +4!, 15) = mod(1 +2 +6 +24, 15)

= mod(33, 15) = 3

The remainder is 3.

3 0

3 years ago

Identify the error by providing a brief description. Then, complete the problem correct

Ipatiy [6.2K]

Answer:

True answer: -24

Step-by-step explanation:

Showing the error

-16-2(-2) – 12 First you need to multiply

8(-2) - 12 The error here is that the wrong numbers are multiplied together

-16-12 Add the negatives together

-28 Your answer (the incorrect one)

The correct way of solving it

-16 -2(-2) - 12 Multiply into the parenthesis

-16 + 4 -12 Add the first two numbers

-12 - 12 Add the numbers together

-24 The answer

8 0

3 years ago

Describe the translation of the function from the parent function f(x) = x².

kkurt [141]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\

\end{array}\\$

$\bf \begin{array}{llll}
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}
$

now, notice the template above... now let's see your function $\bf y=x^2+4\implies 
\begin{array}{llllll}
y=&1(&1x&+&0)^2+&4\\
&A&B&&C&D
\end{array}$

so.. what do you think was the shift then?

8 0

3 years ago

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Korolek [52]

I don’t know sorry but like how’s yoonbum doing? Also like wanna be friends?

4 0

3 years ago