Question

There are 3 consecutive integers twice the first is 20 more than the second. Find the largest number

Answer 1

Let's say "n" is a natural number. {1,2,3,4,..} To ensure we have an even number we will multiply "n" by 2. Two times any number will make an even number.

consecutive even numbers are like; 2, 4, 6, 8, 10 .. etc. Add +2 to the previous number to get the next consecutive.

1st even number = 2n
2nd even number = 2n + 2
3rd even number = 2n + 4

twice the first number (2n) is 20 more then the second (2n + 2).

2(2n) = 2n + 2 + 20

4n = 2n + 22

4n - 2n = 22

2n = 22

n = 11

Now use n = 11 to find the 3 consecutive even numbers.

1st even number = 2(11) = 22
2nd even number = 2(11) + 2 = 24
3rd even number = 2(11) + 4 = 26

22, 24, 26