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Alja [10]
3 years ago
12

What's the vertex and is it a max or min

Mathematics
2 answers:
MrRa [10]3 years ago
5 0
A vertex can be the max or min. The vertex is the highest point or lowest point of a function.
ivann1987 [24]3 years ago
4 0

Answer:

the vertex is (-2,0), and the max or min is (-2,0)

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Write (8a-^3) -2/3 in simplest form
Anna71 [15]

(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

(8a^{-3})^{\frac{-2}{3}

We have to write in simplest form

<em><u>Use the following law of exponent</u></em>

(a^m)^n = a^{mn}

Using this, simplify the given expression

(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}

Thus the given expression is simplified

8 0
3 years ago
Please help me asappp (will give brainiest!)
ryzh [129]

Answer:

TanФ=-1.793

Step-by-step explanation:

Sin^{2} (A) + Cos^{2} (A) = 1

Sin(A)=\sqrt{1-Cos^{2} (A)}

Tan(A) = \frac{Sin(A)}{Cos(A)}

Tan(A) =\frac{\sqrt{1-Cos^{2}(A) } }{Cos(A)} \\Tan(A) =\frac{\sqrt{1-(-.487)^{2} } }{-.487}=-1.793433202

3 0
3 years ago
1. question in attachment
skelet666 [1.2K]
Was there a chart with this?
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3 years ago
What is the value of the variable in the equation, 83=y-99 *
soldier1979 [14.2K]

Answer: y= 182

Step-by-step explanation:

flip equation (y-99=83) and add 99 to both sides. the two 99's will cancel and 83+99 is 182 whihc is the answer.

5 0
3 years ago
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8 0
4 years ago
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