None, the only correct answer is...
-2 > -12
... in negative integers, the smaller the magnitude the bigger it is.
Answer:
1. The volume of the pile is 4,399.7719 m^3
2. The number of sanders to be filled from a pile is 638
Step-by-step explanation:
Here, we firstly would calculate the volume of the pile
Mathematically, that will be;
V = 1/3 * pi * r^2 * h
from the question, h = 14.2
Mathematically, r = d/2
r = 34.4/2 = 17.2 m
So the volume will be:
V = 1/3 * 3.142 * 17.2^2 * 14.2
V = 4,399.7719 m^3
To find the number of sanders to be filled,
we simply divide the volume obtained by the volume a sander can take
That will be;
4,399.7719/6.9
= 637.6 which is 638
Answer:
Marius is right.
Step-by-step explanation:
So although what Khalil said could be correct, they didn't say it right. It would be any two numbers the same distance from 0 <u>going the opposite ways</u>, which means that if you had 3 on one side, you would have -3 on the other side. BUt since Khalil said it wrong, he's basically saying that you can do 3+3 because they're both the same distance away from 0. or you could do (-3)+(-3)=-6 which would still work because they're the same distance away from 0. So unless you just skipped on that part while typing the question, Marius is correct.
Answer: 18
Step-by-step explanation: Well <u><em>percent</em></u> means <em>over 100</em> so we can set up an equation for this problem by reading it from left to right.
<em>What</em> means <em>x</em>, <em>is</em> means <em>equals</em>, <em>30%</em> is <em>30/100</em>, <em>of</em> means <em>times</em> <em>250</em>.
Simplifying on the right side of the equation,
notice that 30/100 reduces to 3/10.
So we have x = 3/10 · 60. Think of the 60 as 60/1 so we can cross-cancel the 60 and 10 to 6 and 1 and we have x = 
or <em>x = 18</em>.
Now let's check our answer back in the original problem to see if it makes sense. We have <em>18 is 30% of 60</em>.
Well we know that 100% of 60 would be 60 so 30% of 60 should be alot less than 60 so 18 seems to make sense as a pretty good answer.
