Solving a compound inequality for this solution gives solution as;
13 daytime cameras and 7 flash cameras or 7 daytime cameras and 13 flash cameras
<h3>How to solve inequality problems?</h3>
Let the number of daytime cameras be x
Let the number of flash cameras be y
Thus, we have;
x + y = 20 ------(1)
Now, daytime cameras costs 2.75 dollars and the flash camera costs 4.25 dollars and you want to spend between 65 and 75 dollars, inclusive. Thus, the inequality to represent this are;
2.75x + 4.25y ≥ 65 and 2.75x + 4.25y ≤ 75
Solving the 3 compound inequalities simultaneously, we can say that the approximate values of the numbers of cameras are;
13 daytime cameras and 7 flash cameras or 7 daytime cameras and 13 flash cameras
Read more about Inequalities at; brainly.com/question/25275758
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Answer:
x1=(-4+5i)/2
x2=(-4-5i)/2
Step-by-step explanation:
4x^2 +16x+49=8
4x^2+16x+49-8=0
4x^2 +16x+41=0
a=4, b=16, c=41
x1=(-b+sqrt(b^2-4ac))/2a
x2=(-b-sqrt(b^2-4ac))/2a
x1=(-16+sqrt(16^2-4*4*41))/2*4
x1=(-16+sqrt(256-656))/8
x1=(-16+sqrt(-400))/8
x1=(-16+20i)/8
x1=(-4+5i)/2
x2=(-4-5i)/2
x = 15 and y = 12
4x + 2 = 62 ( alternate congruent angles )
subtract 2 from each side
4x = 60 ( divide both sides by 4 )
x = 15
12y = 144 ( alternate congruent angles )
divide both sides by 12
y = 12
Answer:
i say it is a
Step-by-step explanation: