Answer: c
Step-by-step explanation:
because to find the average is to add all your numbers up and to divide them by how many numbers you have
and the median is the finding the middle which is the average you line them up from lowest to greatest value and cross one off from the beginning and one from the end until you are left either one or two values
<u>Given</u>:
Given that the circle is graphed with center (-1,1)
We need to determine the equation of the circle.
<u>Radius</u>:
To determine the radius of the circle, let us simply count the number of units between the center point to any point on the circle.
Hence, from the figure, it is obvious that there are 5 units between the center and any point on the circle.
Thus, radius of the circle is 5 units.
<u>Equation of the circle:</u>
The standard form for the equation of the circle is given by

where the center is (h,k) and radius is r.
Substituting the center (-1,1) and r = 5 in the above formula, we get;


Thus, the equation of the circle is 
Answer:
<h2>B. x² + 3x - 5</h2>
Step-by-step explanation:

I am not sure but I do know that you need to have coordinates points in order to be able to graph... so there for you have to make an x/y chart in order to know here to graph...