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Ulleksa [173]
3 years ago
15

Consider the following equations x=4/t and y = 4-t^2 a. Solve the equation for y (eliminate the parameter.)​

Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0

Answer:

y=-16^a/x^2 + 4

Step-by-step explanation:

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Which one doesn't belong? <br><br> A.3:4<br> B.4:3<br> C.chicken nuggets <br> B.dots
maxonik [38]

Answer:

C

Step-by-step explanation:

3:4

4:3

and the dots are 4:3

6 0
3 years ago
A system of equations has no solution. if y=8x+7
Black_prince [1.1K]
And y=8x+c where c≠7
or
8x-y=-c where c≠7
3 0
4 years ago
Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. Since this is a polynomial of degree 4
Art [367]

We are given polynomial function f(x)=x^4-x^3-19x^2-x-20

We are given two zeros -4 and 5.

Therefore, x=-4 and x=5 is given.

So, the two factors of the polynomial will be (x+4)(x-5).

Let us write some steps to factor the given polynomial.

Let us take above factor (x+4) first.

On factoring (x+4) we get factors

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x^3-5x^2+x-5\right)

\mathrm{:Let \ us \ factor}\:x^3-5x^2+x-5 \ now.

Grouping

=\left(x^3-5x^2\right)+\left(x-5\right)

Factoring out gcf from each group, we get

=x^2\left(x-5\right)+\left(x-5\right)

=\left(x-5\right)\left(x^2+1\right)

So, the final factored form of given polynomial will be

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x-5\right)\left(x^2+1\right)

For first to factors (x+4) and (x-5) we have given roots: -4 and 5.

Let us find the root of third factor we got.

x^2+1=0

Subtracting both sides by 1.

x^2 = - 1.

On taking square root on both sides, we get a square root(-1)

x=\sqrt{-1}=+ i and -i.

Those are imaginary solutions.

Therefore, correct option is B) No, there are two imaginary solutions.



5 0
4 years ago
Which one bigger 0.17 or0.165
wel
0.17.

Look at the numbers they have the same. They both start with 0.01...but the next number in the first one is 7, which is greater than 6.
3 0
3 years ago
Read 2 more answers
Answer pleaseeeee<br> Find the value of x in the triangle shown below.
Maurinko [17]

well, keeping in mind that twin sides stemming from the same "vertex" make twin angles at the "base", Check the picture below.

7 0
1 year ago
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