All categories

3 years ago

Which one doesn't belong? A.3:4 B.4:3 C.chicken nuggets B.dots

Mathematics

1 answer:

maxonik [38]3 years ago

6 0

Answer:

Step-by-step explanation:

3:4

4:3

and the dots are 4:3

You might be interested in

Jordan places two boards end to end to make one shelf. The first board is 47-100 meter long.The second board is 5-10 meter long.

puteri [66]

The fraction 5/10 is the same as 50/100 because they are equivalent. It will take 10 group of 10 to get to the denominator 100, so it will take 10 groups of 5 in the numerator to make it equal.

The answer is 50/100.

4 0

3 years ago

CAN SOMEONE PLEASE HELP AND EXPLAIN THIS

lord [1]

Answer:

what are the options? I'll say it in the comments

7 0

3 years ago

Read 2 more answers

A. volume B. perimeter C. area

Solnce55 [7]

Answer:

<h3>B. perimeter</h3>

Step-by-step explanation:

I think this would make the most sense.

8 0

3 years ago

angles FGH and angles PQR are vertical angles. If angles FGH is 29, what is the measure of angles PQR?

steposvetlana [31]

Answer:

< PQR = 61°

Step-by-step explanation:

Hope this helps:)

3 0

2 years ago

What are the minimum, first quartile, median, third quartile, and maximum of the data set? 2, 13, 17, 14, 9, 3, 16, 12

Alex777 [14]

So before anything, rearrange the data so that it's in ascending order: {2,3,9,12,13,14,16,17}

Next, the minimum and maximum are as they seem: the smallest and largest numbers in the data. Looking at our data, 2 is our minimum and 17 is our maximum.

Next, to find the median, find the number that is in the middle of the data set. If there isn't one number in the middle, find the average of the two middle numbers to get your median:

$\{2,3,9,\overbrace{\boxed{12,13,}}^{\textsf{middle numbers}}14,16,17\}\\\\\frac{12+13}{2}\\\\\frac{25}{2}\\\\12.5$

The median is 12.5.

Next, to find the first quartile, or the lower quartile, find the "median" of the numbers to the left of the median.

$\overbrace{\{2,\boxed{3,9,}12,}^{\textsf{left of median}}13,14,16,17\}\\\\\frac{3+9}{2}\\\\\frac{12}{2}\\\\6$

The first quartile is 6.

Next, to find the third quartile, or the upper quartile, find the "median" of the numbers to the right of the median.

$\{2,3,9,12,\overbrace{13,\boxed{14,16,}17\}}^{\textsf{right of median}}\\\\\frac{14+16}{2}\\\\\frac{30}{2}\\\\15$

The third quartile is 15.

3 0

3 years ago