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Alexandra [31]
3 years ago
7

Find the rule. Solve for n

Mathematics
1 answer:
Serga [27]3 years ago
3 0
Is there more to this question?
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Given f(x)=-2/3x+3 and g(x)=-2x^2-5
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2/3 give 3 with a g(8) 25 real

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Solve by using the measurements ∠PQR = 90°, ∠QRP = 80°, and r = 15. Round measures of sides to the nearest tenth and measures of
valkas [14]

Good evening ,

___________________

Step-by-step explanation:

Look at the photo below for the answer.

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15% of a mass is 45 g. Calculate 20% of the mass
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What is 100% of the mass ?

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3 years ago
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An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
A group of hickers buys 8 bags of mixed nuts wash bag contains 3 1/2 cups of mixed nuts. The mixed nuts are shared evenly among
Paul [167]

Answer:

2 1/3 cups

Step-by-step explanation:

The total number of cups of mixed nuts purchased is ...

(8 bags)·(3 1/2 cups/bag) = 8·3.5 cups = 28 cups

When those are shared 12 ways, each share is ...

(28 cups)/(12 shares) = (28/12) cups/share = 2 1/3 cups/share

Each share is 2 1/3 cups.

3 0
3 years ago
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