Fill in the blank for this graph.

Question 5 (1 point)

riadik2000 [5.3K]

Answer:

The area of sector AOB is 75.36 unit²

Step-by-step explanation:

Consider the provided information.

Circle O with minor arc AB=60 degrees and OA =12.

We need to find the area of sector.

Area of the sector: $A=\frac{\theta }{360} \times \pi r^2$

Substitute $\theta=60$ and r =12 in above formula.

$A=\frac{60}{360} \times 3.14\times (12)^2$

$=\frac{1}{6} \times 3.14\times 144$

$=24\times 3.14$

$=75.36$

Hence, the area of sector AOB is 75.36 unit²

8 0

3 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

3 years ago

2.

Lynna [10]

In 15 minutes, Jada would have covered about 2.5 miles, while the cousin would have covered 0.625 miles.

<h3>What is speed?</h3>

Speed is the ratio of distance to time.

For Jada:

Speed = 2 miles / 12 minutes = 0.167 miles per minute

For Jada cousin:

Speed = 1 mile / 24 min = 0.0417 miles per minute.

Hence, in 15 minutes:

Jada distance = 15 min * 0.167 miles per minute = 2.5 miles

Jada cousin distance = 15 min * 0.167 miles per minute = 0.625 miles

In 15 minutes, Jada would have covered about 2.5 miles, while the cousin would have covered 0.625 miles.

Find out more on speed at: brainly.com/question/4931057

6 0

2 years ago

Help me please geometry class

artcher [175]

Answer:

m∠ADB = 59°

Step-by-step explanation:

I've provided my work which also includes how I check my answers by using the information given! Hope this helps!!! If you have any questions, I can try to help.

6 0

2 years ago

Which are true of the function f(x) = 49(1/7)^x Check all that apply.

Karolina [17]

The given function is : y= f(x) =49 [\frac{1}{7}]^x

The statements which are true regarding this function is

1. As you can observe that y is defined for all values of x , so Domain is set of all values that x can take which is set of all real numbers.

2. Also, x =\frac {\log[\frac{y}{49}]}{-\log7}, so x is defined for all values of y. Range is all values that y can take which is also set of all real numbers greater than zero, i.e y>0.

As ,x =0 then y= 49 and x_{1} =1 then y_{1} = 7,

so ,y_{1} = \frac{y}{7}.

So, Option (1),(4) and (5) are correct.

8 0

2 years ago

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