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pshichka [43]
3 years ago
5

Fill in the blank for this graph.

Mathematics
1 answer:
Agata [3.3K]3 years ago
4 0

Answer:

2.22

Step-by-step explanation:

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3m - 3 divided by 3 for m=8
KengaRu [80]

Answer:

Either 7 or 23 - read note

Step-by-step explanation:

Substitute m for 8.

*Note: I'm not sure if anything is in parentheses so there are two possible answers depending on whether you want it done left to right or by order of operations*

Left to Right:

3(8) - 3 ÷ 3

24 - 3 ÷ 3

21 ÷ 3

7

Order of Operations:

3(8) - 3 ÷ 3

24 - 3 ÷ 3

24 - 1

23

6 0
3 years ago
Read 2 more answers
Triangle ABC contains the point A(5,2). Find the coordinates of A' after a reflection over the x-axis
Sholpan [36]

Answer:

Step-by-step explanation:

Should be 5,-2 OR NOT

4 0
4 years ago
What expression is equivalent
Citrus2011 [14]

Answer:

-4x^2, -3x, -5

Step-by-step explanation:

-4x^2 + 2x - 5 (1 + x)

-4x^2 + 2x - 5 + 5x

-4x^2 - 3x - 5

3 0
3 years ago
Is y=y+8 even, odd, or neither
SIZIF [17.4K]

The expression y = y + 8 does neither represent an odd number nor an even number.

<h3>Does represent a given equation an even or odd number or neither?</h3>

In this problem we must check if a given algebraic equation represents an even number or an odd number or neither by using algebraic means. Even numbers are integers, whose last digit is 0, 2, 4, 6 or 8, whereas odd numbers are integers, whose last digit is 1, 3, 5, 7 or 9. Now we proceed to  check the expression:

y = y + 8                     Given

y + (- y) = 8                 Compatibility with addition / Existence of additive inverse / Modulative property

0 = 8                           Existence of additive inverse / Modulative property / Result

The expression y = y + 8 does neither represent an odd number nor an even number.

To learn more on even numbers: brainly.com/question/2289438

#SPJ1

3 0
1 year ago
PLEASE ANSWER QUICKLY
Olegator [25]

Answer:

x=3

Step-by-step explanation:

Set equations equal to each other:

x^3-3x^2+2=x^2-6x+11

Subtract two from both sides

x^3-3x^2=x^2-6x+9
Factor out x^2 from the left side

x^2(x-3)=x^2-6x+9

Factor the right side, look for two factors of 9, which add to -6, which is just -3 and-3

x^2(x-3) = (x-3)(x-3)

So as you can see here, we have both sides in factored form, and both have a factor of (x-3) on both sides, and if one of the factors is zero, then the entire thing becomes zero, since 0 * anything= zero.

this means a solution would be at x=3, since it makes the right side 0 * 0 = 0, and the left side (3)^2 * 0 = 0

It's important to notice this, since had we divided by x-3 to make the equation a quadratic, we would've excluded this real solution, because when dividing by x-3 the solution x=3 makes it 0, so we would've been dividing by zero.

So one of the real solutions is at x=3

6 0
2 years ago
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