Answer:
Since both terms are perfect squares, factor using the difference of squares formula,
a
^2
−
b
^2
=
(
a
+
b
)
(
a
−
b
)
where
a
=
y
and
b
=
6
(
y
+
6
)
(
y
−
6
)
Step-by-step explanation:
(1+3x-1)×{1-(3x-1)}
=3x.(1-3x+1)
=3x.3x
=9x^2.
The cross product of two vectors gives a third vector

that is orthogonal to the first two.

Normalize this vector by dividing it by its norm:

To get another vector orthogonal to the first two, you can just change the sign and use

.
The given expression :

For coordinates:
put x = 0 then :

Coordinate : (x, y) = (0, 1)
Put x= 1 and simplify :

Coordinate : (x, y) = ( 1, 0.5)
Put x = (-2) and simplify :

Coordinate : (x, y) = ( -2, 4)
Put x = (-3) and simplify :

Coordinate : (x, y) = (-3, 8)
Substitute x = (-1) and simplify :

Coordinate : (x, y) = ( -1, 2)
So, the coordinates are :
The graph is :
Answer:
13x
Step-by-step explanation:
you would just add the 2 numbers together and then keep the variable. if you know the variable (if there’s a sheet to go off of) then multiply and add but otherwise it’s just 8 + 5 then add an x. 13x