There's an identity
sec^2 x = 1 + tan^2 x
so here we have
sec^2 theta = 1 + (3/8)^2 = 73/64
sec theta = sqrt 73 / 8 or 1.068 to nearest thousandth
<u><em>Answer:</em></u>
Nelson burned the most calories per hour
<u><em>Explanation:</em></u>
To solve this question, we will get the amount calories burned by each in one hour and then compare the two values
To do this, we will divide the total amount of calories burned by the total time
<u>1- For Sabra:</u>
We are given that she burnt 845 calories in
(which is equivalent to 3.25) hours
<u>Therefore:</u>
Calories burnt in an hour =
calories/hour
<u>2- For Nelson:</u>
We are given that he burnt 1435 calories in
(which is equivalent to 4.875) hours
<u>Therefore:</u>
Calories burnt in an hour =
calories/hour
<u>3- Comparing the two values:</u>
From the above calculations, <u>we can deduce that</u> Nelson burned the most calories per hour
Hope this helps :)
Answer:
https://cdn.erblearn.org/pdf/www/WTE_Middle_September2018_FINAL.pdf
Step-by-step explanation:
This may be it! Sorry, I didn’t take the ISEE, I only took the SHSAT! I’ll keep looking for it!
Answer: 90 students
Step-by-step explanation:
I got this question on my test, and the answer was 90
100% verified! :D
Answer
6 is the nearest tenth it did not say ten it said ten-th