Find the center and radius for the circle defined by the equation: x2+y2+1/2x-2y-5=0.
1 answer:
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In place of t, or theta, I'm going to utilize x instead. So the equation is -3*cos(x) = 1. Get everything to one side and we have -3*cos(x)-1 = 0
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
Answer:
Step-by-step explanation:
The formula for distance is:
Where (x₁, y) and (x₂, y₂) are the points.
We are given (-6, 6) and (-3, 3). If we match the value and its corresponding variable, we see that:
- x₁= -6
- y₁ = 6
- x₂ = -3
- y₂ = 3
Substitute the values into the formula.
Solve inside the parentheses.
- -3 --6 = -3+6 = 3
- 3-6 = -3
Solve the exponents.
- (3)²= 3*3= 9
- (-3)²= -3*-3 =9
Add.
Round to the nearest tenth. The 4 in the hundredth place tells us to leave the 2 in the tenth place.
The distance between the two points is apprximately <u>4.2</u>