Quadrant IV is also known as the 4th quadrant. Imagine it like a C: 1st quadrant is in the top right, 2nd quadrant is in the top left, 3rd quadrant is in the bottom left, and the 4th quadrant is in the bottom right. With this information in mind, the answer is A) P, B, K
The 2 smallest lengths in a triangle have to add up to be greater that the longest side of the triangle. In this case, the longest side is 20. The 2 smallest sides are 5 and 10. 5+10=15, but 15<20. This is why these 3 lengths can’t create a triangle.
Answer: its x = 3
Step-by-step explanation:
The maximum or minimum of a quadratic function occurs at
x
=
−
b
2
a
. If
a
is negative, the maximum value of the function is
f
(
−
b
2
a
)
. If
a
is positive, the minimum value of the function is
f
(
−
b
2
a
)
.
f
min
x
=
a
x
2
+
b
x
+
c
occurs at
x
=
−
b
2
a
Find the value of
x
equal to
−
b
2
a
.
x
=
−
b
2
a
Substitute in the values of
a
and
b
.
x
=
−
−
12
2
(
2
)
Remove parentheses.
x
=
−
−
12
2
(
2
)
Simplify
−
−
12
2
(
2
)
.
Tap for more steps...
x
=
3
The maximum or minimum of a quadratic function occurs at
x
=
−
b
2
a
. If
a
is negative, the maximum value of the function is
f
(
−
b
2
a
)
. If
a
is positive, the minimum value of the function is
f
(
−
b
2
a
)
.
f
min
x
=
a
x
2
+
b
x
+
c
occurs at
x
=
−
b
2
a
Find the value of
x
equal to
−
b
2
a
.
x
=
−
b
2
a
Substitute in the values of
a
and
b
.
x
=
−
−
12
2
(
2
)
Remove parentheses.
x
=
−
−
12
2
(
2
)
Simplify
−
−
12
2
(
2
)
.
Tap for more steps...
x
=
3
Answer:
The equation of the required line is y = x + 5
Step-by-step explanation:
The equation of the given line is y = x - 2
The required line = A line parallel to the given line
The point through which the required line passes = (-3, 2)
The general form of the equation of a straight line, is y = m·x + c
Where;
m = The slope of the line
By comparison, the slope of the given line, m = 1
When two lines are parallel, their slope are equal
Therefore, the slope of the required line = m = 1
The equation of the required line in point and slope form is therefore;
y - 2 = x - (-3) = x + 3
∴y = x + 3 + 2 = x + 5
The equation of the required line is therefore;
y = x + 5.
Angles T and V of the parallelogram are equal to 91°.
Calculating the Value of x
In the parallelogram TUVS, adjacent angles U and V are given as,
U = 4x+9
V = 6x-29
Since U and V are adjacent angles, and as per the properties of a parallelogram, sum of adjacent angles is equal to 180°.
4x+9 + 6x-29 = 180
10x - 20 =180
10x = 200
x = 20
Calculating the Angles of the Parallelogram
∠U = 4x + 9
∠U = 4(20) + 9
∠U = 80 + 9
∠U = 89°
∠V = 6x - 29
∠V = 6(20) - 29
∠V = 120 - 29
∠V = 91°
According to the properties of a parallelogram, opposite angles are of equal measure.
∴ ∠T = ∠V and ∠S = ∠U
⇒ ∠T = 91° and ∠S = 89°
Learn more about a parallelogram here:
brainly.com/question/1563728
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