All categories

1 year ago

a 12 ounce sports drink costs $.99, and a 16 ounce sports drink cost $1.19. which size is the bes to buy

Mathematics

1 answer:

Wewaii [24]1 year ago

8 0

Answer: 16 ounce sports drink

Step-by-step explanation:

Calculate cost per ounce for both sizes.

12 ounce sports drink:

$0.99 / 12 ounces = $0.0825 per ounce

16 ounce sports drink:

$1.19 / 16 ounces = $0.074375 per ounce

Therefore, the 16 ounce sports drink is a better but because it is cheaper per ounce.

You might be interested in

A cylinder has a volume of 198 cm3, and its

xz_007 [3.2K]

Answer:

height= 9 cm

Step-by-step explanation:

6 0

3 years ago

The area of a rectangular park is 3/5 sq. mile

Readme [11.4K]

Answer:

3/5=7/8x

=24/35

(you literly put the answer why are u asking this???)

Hope This Helps!!!

7 0

2 years ago

Consider a system with one component that is subject to failure, and suppose that we have 120 copies of the component. Suppose f

saveliy_v [14]

Nsnsnsnssnsnsnsbdbdbdbdbdhdhdhhddh

3 0

2 years ago

What are the factors of the expression (y-2)(x+3)?

masya89 [10]

Answer:

Something which is multiplied by something else. A factor can be a number, variable, term, or a longer expression

with this information we can conclude that the numbers 2 and 3 are factors

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Solve 4^x-5 = 6 for x using the change of base formula log base b of y equals log y over log b

Ronch [10]

Answer:

$4^x-5=6$ gives the solution $x=\frac{\log(11)}{\log(4)}$ .

$4^{x-5}=6$ gives the solution $x=\frac{\log(6)}{\log(4)}+5$ .

Step-by-step explanation:

I will solve both interpretations.

If we assume the equation is $4^{x}-5=6$ , then the following is the process:

$4^x-5=6$

Add 5 on both sides:

$4^x=6+5$

Simplify:

$4^x=11$

Now write an equivalent logarithm form:

$\log_4(11)=x$

$x=\log_4(11)$

Now using the change of base:

$x=\frac{\log(11)}{\log(4)}$ .

If we assume the equation is $4^{x-5}=6$ , then we use the following process:

$4^{x-5}=6$

Write an equivalent logarithm form:

$\log_4(6)=x-5$

$x-5=\log_4(6)$

Add 5 on both sides:

$x=\log_4(6)+5$

Use change of base formula:

$x=\frac{\log(6)}{\log(4)}+5$

6 0

3 years ago