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OlgaM077 [116]
3 years ago
12

Please find the slope of (-2, 4) and (3, -5)

Mathematics
1 answer:
DIA [1.3K]3 years ago
8 0

Answer:

The slope of the line = m = -9/5

Step-by-step explanation:

Given the points

  • (-2, 4)
  • (3, -5)  

Determining the slope between (-2, 4) and (3, -5)

(x₁, y₁) = (-2, 4)

(x₂, y₂) = (3, -5)

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]  

                 =  [-5 - 4] / [3 - (-2)]

                 = [-9] / [3 + 2]

                 = -9/5

Thus, the slope of the line = m = -9/5  

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PLEASE SHOW YOUR WORK!!! (solve system of equations by adding, subtracting, or multiplying.)
Aliun [14]
Hey friend, hope I can assist you!
I will solve by elimination <3.
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6x - 14y = 4
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So 6x - 14 * 1 = 4
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6x - 14 = 4
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3 years ago
Solving for matrices
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Answer:

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Step-by-step explanation:

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\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\5&-4&4&|&-7\end{array}\right)

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\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&6&-6&|&18\end{array}\right)

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\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&1&-1&|&3\end{array}\right)

Now multiply  the third equation by 26 and add it to the second row:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&0&-45&|&-90\end{array}\right)

You get the system of three equations:

\left\{\begin{array}{r}3x-4y-5z=-27\\-26y-19z=-168\\-45z=-90\end{array}\right.

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