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Tasya [4]
3 years ago
5

The box plots show the data distributions for the number of customers who used a coupon each hour during a two-day sale.

Mathematics
1 answer:
Marina86 [1]3 years ago
5 0

Answer:

Interquartile age

Step-by-step explanation:

The box plots that is being referred to are missing, however, we can still answer this without the box plots.

The appropriate measure of variability that can be easily determined by a box plot is the interquartile range. Which is the difference between the 3rd quartile and the 1st quartile.

On a box plot, the first quartile is the data value ta the beginning of the edge of the rectangular box while the third quartile is at the end of the edge of the rectangle box. So, this makes is easy for use interquartile range as a measure of variability when comparing both.

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A car rental company has two rental rates. rate 1 is $64 per day pluus $.16 per mile. rate 2 is $128 per day plus $.08 per mile.
kvv77 [185]
D is days
m is miles

0.16m + 64d (this is rate 1)
0.08m + 128d ( this is rate 2)

since you plan to rent for one day, input d as 1.

0.16m + 64(1)
0.08m + 128(1)

i hope i gave you enough hints
7 0
4 years ago
What are the answers to a. ,b. , &c.
Julli [10]
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4 years ago
Use the Alternating Series Approximation Theorem to find the sum of the series sigma^infinity_n = 1 (-1)^n - 1/n! with less than
DanielleElmas [232]

Answer:

\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n!} = 1-0.5+0.16667-0.04167 +0.00833-0.001389 +0.000198 -0.0000248

For the 7th term we have 3 decimals of approximation but our value is 0.000198 higher than the error required, so we can use the 8th term and we have that |-0.0000248|= 0.0000248 and with this we have 4 decimals of approximation so if we add the first 8 terms we have a good approximation for the series with an error bound lower than 0.0001.

\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n!} = 1-0.5+0.16667-0.04167 +0.00833-0.001389 +0.000198-0.0000248 =0.632118

Step-by-step explanation:

Assuming the following series:

\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n!}

We want to approximate the value for the series with less than 0.0001 of error.

First we need to ensure that the series converges. If we have a series \sum a_n where a_n = (-1)^n b_n [/tex] or a_n =(-1)^{n-1} b_n where b_n \geq 0 for all n if we satisfy the two conditions given:

1) lim_{n \to \infty} b_n =0

2) {b_n} is a decreasing sequence

Then \sum a_n is convergent. For this case we have that:

lim_{n \to \infty} \frac{1}{n!} =0

And \frac{1}{n!} because \frac{1}{n!} =\frac{1}{n (n-1)!} and \frac{1}{n(n-1)!} < \frac{1}{(n-1)!}

So then we satisfy both conditions and then the series converges. Now in order to find the approximation with the error required we can write the first terms for the series like this:

\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n!} = 1-0.5+0.16667-0.04167 +0.00833-0.001389 +0.000198 -0.0000248

For the 7th term we have 3 decimals of approximation but our value is 0.000198 higher than the error required, so we can use the 8th term and we have that |-0.0000248|= 0.0000248 and with this we have 4 decimals of approximation so if we add the first 8 terms we have a good approximation for the series with an error bound lower than 0.0001.

\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n!} = 1-0.5+0.16667-0.04167 +0.00833-0.001389 +0.000198-0.0000248 =0.632118

6 0
4 years ago
Someone please please please help me on this it’s due right now!
OLEGan [10]

Answer:

<h2>18.15</h2>

Step-by-step explanation:

Add what they say to add. The first equation they give you is the answer.

4 0
3 years ago
PLEASE HELP IM IN A BIG HURRY
Pepsi [2]
First, change the fraction (decimal and percent) into gallon
Martha used 17% of the total oil, that means
Martha = 17% × 8 gallons
Martha = 0.17 × 8 gallons
Martha = 1.36 gallons

Brett used 0.18 of the total oil
Brett = 0.18 × 8 gallons
Brett = 1.44 gallons

Mike used 0.7 gallons

Second, compare the number of gallon they used
1.36
1 acts as ones
3 acts as tenths
6 acts as hundreths

1.44
1 acts as ones
4 acts as tenths
4 acts as hundreths

0.7 or 0.70
0 acts as ones
7 acts as tenths
0 acts as hundreths

Compare the ones, 1.44 and 1.36 both have 1 as the ones, however 0.7 has 0 as ones. Because 1 is greater than 0, 1.44 and 1.36 are greater than 0.7.
Now compare the tenth, 1.44 has 4 as the tenths, and 1.36 has 3 as the tenths. Because 4 is greater than 3, 1.44 is greater than 1.36.
1.44 > 1.36 > 0.7
Brett > Martha > Mike
Brett used the greatest amount of oil
7 0
3 years ago
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