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lozanna [386]
3 years ago
13

Charlie runs at a speed of 3 yards per second . About how many miles per hour does Charlie run?

Mathematics
2 answers:
MrMuchimi3 years ago
6 0
Ok so this can get tricky, it is basically just asking for you to perform many unit conversions. I'll try to simplify it for you here while still maintaining the explanation. If you have any questions about this process feel free to message me. 

3 yards = ____ miles (conversion factor is 1760 because there are 1760 yards in a mile) 

3/1760 = 0.017 miles,

Now we just need to convert seconds to hours. 

1 second is how many mins, then how many mins in an hour? 

360 seconds in an hour. 

Ok now we just need to combine these two pieces of info, 
0.017/360 = 4.72222 miles per hour. Thus 4.72 is the answer.
Volgvan3 years ago
6 0

Answer:

6.14 miles/hour

Step-by-step explanation:

Charlie runs at a speed of 3 yards per second.

First we have to calculate the speed per hour in yards.

1 hour = 3600 seconds

In one second Charlie runs = 3 yards

in 3600 seconds he runs = 3600 × 3

                                          = 10,800 yards

Since 1760 yards = 1 mile

Hence, 10,800 yards = \frac{10800}{1760}

                                   = 6.13636 ≈ 6.14 miles

Charlie runs at the speed of 6.14 miles per hour.

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Step-by-step explanation:

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The tables represent two linear functions in a system,
Alenkasestr [34]

Answer:

<h2>(8, -22)</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

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b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

First table:

(-4, 26), (0, 10) → b = 10

m=\dfrac{10-26}{0-(-4)}=\dfrac{-16}{4}=-4

\boxed{y=-4x+10}

Second table:

(-4, 14), (0, 2) → b = 2

m=\dfrac{2-14}{0-(-4)}=\dfrac{-12}{4}=-3

\boxed{y=-3x+2}

We have the system of equations:

\left\{\begin{array}{ccc}y=-4x+10&(1)\\y=-3x+2&(2)\end{array}\right\\\\\text{Put (1) to (2):}\\\\-4x+10=-3x+2\qquad\text{subtract 10 from both sides}\\-4x=-3x-8\qquad\text{add 3x to both sides}\\-x=-8\qquad\text{change the signs}\\x=8\\\\\text{Put the value of x to (2):}\\\\y=-3(8)+2\\y=-24+2\\y=-22

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nika2105 [10]

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(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13
jolli1 [7]

Answer:

y(x)=3e^{5x}-2xe^{5x}

Step-by-step explanation:

The given differential equation is y''-10y'+25y=0

The characteristics equation is given by

r^2-10r+25=0

Finding the values of r

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We got a repeated roots. Hence, the solution of the differential equation is given by

y(x)=c_1e^{5x}+c_2xe^{5x}...(i)

On differentiating, we get

y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)

Apply the initial condition y (0)= 3 in equation (i)

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Now, apply the initial condition y' (0)= 13 in equation (ii)

13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2

Therefore, the solution of the differential equation is

y(x)=3e^{5x}-2xe^{5x}

5 0
3 years ago
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