7.849 make the 8 worth 10 times as much
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Answer:
81.85%
Step-by-step explanation:
Given :
The average summer temperature in Anchorage is 69°F.
The daily temperature is normally distributed with a standard deviation of 7°F .
To Find:What percentage of the time would the temperature be between 55°F and 76°F?
Solution:
Mean =
Standard deviation =
Formula :
Now At x = 55
At x = 76
Now to find P(55<z<76)
P(2<z<-1)=P(z<2)-P(z>-1)
Using z table :
P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185
Now percentage of the time would the temperature be between 55°F and 76°F =
Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.
First, in order to find the length of side w, you must first find the angle W.
A triangle must be 180 degrees in total. 93 + 37 makes the triangle only have 130 at the moment.
180 - 130 = 50
So angle W is 50 degrees
Now using this, we can use law of sines.
Now multiply sin 50 on both sides. It can be written like so:
Now plug this in a calculator.
Answer is 39.5
A triangle must be 180 degrees in total. 93 + 37 makes the triangle only have 130 at the moment.
180 - 130 = 50
So angle W is 50 degrees
Now using this, we can use law of sines.
Now multiply sin 50 on both sides. It can be written like so:
Now plug this in a calculator.
Answer is 39.5