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Slav-nsk [51]
3 years ago
8

Rhombus LMNO is shown with its diagonals. Rhombus L M N O is shown. Diagonals are drawn from point M to point O and from point L

to point N and intersect at point P. All sides are congruent. The length of LN is 28 centimeters. What is the length of LP?
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
3 0

In a Rhombus the diagonals intersect and divides it in two equal halves.

Therefore LP = 28/2

LP = 14cm

Answered by GauthMath if you like please click thanks and comment thanks

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A bag of skittles has 50 pieces of candy what percentage is orange ps. there are 11 orange skittles
Oliga [24]

Answer:

I think the answer is 22% but I am not sure

Step-by-step explanation:

Percentage solution with steps:

Step 1: We make the assumption that 50 is 100% since it is our output value.

Step 2: We next represent the value we seek with X

Step 3: From step 1, it follows that 100%=50

Step 4: In the same vein, x%=11.

Step 5: This gives us a pair of simple equations:

100%=50(1).

X%=11(2).

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the left hand side of both equations have the same unit; we have

100% / X% = 11 / 50

X = 22%

Step 7: Taking the inverse (or reciprocal) of both sides yields

X% / 100% = 11 / 50

Therefore, 11 is 22% of 50.

5 0
3 years ago
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Each patron pays an annual fee of $36 to the library. If the library collects $20,304 from the annual fee, how many patrons are
choli [55]

Answer:

564 patrons.

Step-by-step explanation:

20,304/36 = 564

5 0
2 years ago
The average price of a movie ticket in the United States from 1980 to 2000 can be modeled by the expression, 2.75+0.10x, where x
MissTica

Answer:

<h2>$4.7</h2>

Step-by-step explanation:

step one:

Let the cost be y

to solve for the cost of  a movie ticket, we need to solve the expression

y=2.75+0.10x

step two:

given that x is the number of years between 1980-2000

the number of years is 20years

put x= 20 in the expression for the cost we have

y=2.75+0.10(20)

y=2.7+2

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5 0
3 years ago
Suppose a researcher is interested in understanding the variation in the price of store brand milk. A random sample of 36 grocer
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Step-by-step explanation:

Given : Significance level : \alpha: 1-0.95=0.5

Critical value : z_{\alpha/2}=1.96

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Sample mean : \overline{x}=\$\ 3.13

Standard deviation : \sigma= \$\ 0.23

The confidence interval for population mean is given by :_

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

\text{i.e. }\$\ 3.13\pm (1.96)\dfrac{0.23}{\sqrt{36}}\\\\\approx\$\ 3.13\pm0.075\\\\=(\$\ 3.13-0.075,\$\ 3.13+0.075)=(\$\ 3.055,\$\ 3.205)

Hence, the 95% confidence interval to estimate the population mean = ($3.055, $3.205)

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