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ahrayia [7]
3 years ago
13

The velocity of a particle moving along a straight line is given by v(t)=6t2+4t−5 cm/sec at time t seconds with initial position

s(0)=3 cm. What is the position of the particle at t=2 seconds, in cm?
Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0

Answer:

s(2) = 17 cm

Step-by-step explanation:

We are told that the velocity function is;

v(t) = 6t² + 4t − 5 cm/sec

Integral of velocity gives distance.

Thus;

s(t) = ∫v(t) = ∫6t² + 4t − 5

s(t) = 2t³ + 2t² - 5t + c

We are told that s(0)=3 cm

Thus;

s(0) = 2(0)³ + 2(0)² - 5(0) + c = 3

Thus; c = 3

Thus;

s(t) = 2t³ + 2t² - 5t + 3

At t = 2 secs

s(2) = 2(2)³ + 2(2)² - 5(2) + 3

s(2) = 17 cm

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Rasek [7]

<u>Part 1)</u> Use the fact that there are 12 inches in a foot

a) How many inches tall is a 7 foot basketball player?

we know that

1 foot=12 inches

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\frac{12}{1} \frac{inches}{foot} =\frac{x}{7} \frac{inches}{feet} \\ \\x=12*7\\ \\x=84\ inches

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by proportion

\frac{4.20}{2} \frac{\$}{pounds} =\frac{x}{5} \frac{\$}{pounds} \\ \\2*x=4.2*5\\ \\x=4.2*5/2=\$10.5    

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<u>the answer Part 2) is</u>

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<u>Part 3) </u>Janice mother gave her a ten dollars bill to buy five pounds each of bananas and apples at the grocery store. When she got there she found that bananas were 80 c per pound and apples were $1.40 per pound.

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<u>Find the cost of the apples</u>

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\$4+\$7=\$11

\$11 > \$10------> Janice's mother didn't give her enough money

She needs more money

She needs-------> \$11-\$10=\$1

therefore

<u>the answer part 3) is</u>

She needs  \$1 more


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