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blagie [28]
4 years ago
15

Which of the options is a solution for the following system of inequalities?

Mathematics
2 answers:
creativ13 [48]4 years ago
3 0
For it to be a solution, it has to satisfy both inequalities.

using (5,-2)...x = 5 and y = -2

4x + y > 3
4(5) - 2 > 3
20 - 2 > 3
18 > 3.....correct

x - y > 2
5 - 2 > 2
3 > 2....correct

 solution is (5,-2)



marishachu [46]4 years ago
3 0

Answer:

Option D.

Step-by-step explanation:

The given system of inequalities are

4x+y>3

x-y>2

We need to find a solution for the following system of inequalities.

Check each point by these inequalities.

For (-2,-2)

4(-2)+(-2)>3\Rightarrow -10>3 False

So, (-2,-2) is not included in the solution set.

For (1,-5)

4(1)+(-5)>3\Rightarrow -1>3 False

So, (1,-5) is not included in the solution set.

For (0,0)

4(0)+(0)>3\Rightarrow 0>3 False

So, (0,0) is not included in the solution set.

For (5,-2)

4(5)+(-2)>3\Rightarrow 18>3 True

(5)-(-2)>2\Rightarrow 7>2 True

Both inequalities are true for the point (5,-2). So, the point (5,-2) is a solution for the following system of inequalities

Therefore, the correct option is D.

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The larger of two numbers is twice the smaller increased by five. Find the two numbers if three times the larger exceeds double
irina [24]

The larger number is 13 and smaller number is 4

<em><u>Solution:</u></em>

Let the larger number be "a"

Let the smaller number be "b"

<em><u>Given that larger of two numbers is twice the smaller increased by five</u></em>

larger number = twice the smaller increased by five

larger number = twice the smaller number + 5

a = 2b + 5 --- eqn 1

<em><u>Also given that three times the larger exceeds double the smaller by 31</u></em>

Here "exceeds" denotes addition and "times" denotes multiplication

"double" denotes being multiplied by 2

three times the larger number = double the smaller number + 31

3a = 2b + 31 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "b"</u></em>

Substitute eqn 1 in eqn 2

3(2b + 5) = 2b + 31

6b + 15 = 2b + 31

6b - 2b = 31 - 15

4b = 16

<h3>b = 4</h3>

From eqn 1,

a = 2b + 5

a = 2(4) + 5

a = 8 + 5

<h3>a = 13</h3>

Thus the larger number is 13 and smaller number is 4

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Answer:

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Step-by-step explanation:

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