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3 years ago

Can u help me solve this

Mathematics

2 answers:

nasty-shy [4]3 years ago

6 0

Answer:

V = 5,324 in^3

Step-by-step explanation:

V = 4( $\pi$ r^3)/3

= 4(3)(11^3)/3

= 12(11)(11)(11)/3

= 12(1,331)/3

= 15,972/3

V = 5,324 in^3

Gala2k [10]3 years ago

6 0

Answer:

5575.28 or 5,324 depending on use of pie.

Step-by-step explanation

V=4/3πr3=4/3·π·113≈5575.27976

Hope this helps :)!

This is the answer if pie is used as 3.14.

V = 5,324 in^3 if pie used as 3.

V = 5575.28 in^3 if pie used as 3.14.

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the force keeping the moon in its orbit round the earth is inversely proportional to the square of the distance from the earth.i

ludmilkaskok [199]

9514 1404 393

Answer:

F = 3.84×10^23/R²

Step-by-step explanation:

No units are given for distance, so we cannot give a constant of proportionality that has suitable units.

The general form for inverse square variation is ...

F = k/R²

Then the value of k can be found from ...

k = F·R² = (6×10^5)(8×10^8)^2 = 3.84×10^23

The formula relating the given F and R is ...

F = 3.84×10^23/R²

3 0

3 years ago

5. Suppose that a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organ

mart [117]

Answer:

Probability that the sample proportion will be greater than 0.5 is 0.8133.

Step-by-step explanation:

We are given that the a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organization is about to take a simple random sample of voters and will use the sample proportion to estimate p.

Suppose that the polling organization takes a simple random sample of 500 voters.

Let $\hat p$ = sample proportion

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = population proportion = 48%

n = sample of voters = 500

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample proportion will be greater than 0.5 is given by = P( $\hat p$ > 0.50)

P( $\hat p$ > 0.50) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < $\frac{0.50-0.48}{\sqrt{\frac{0.50(1-0.50)}{500} } }$ ) = P(Z < 0.89) = 0.8133

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.89 in the z table which has an area of 0.8133.