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4 years ago

ASAP! PLS HELP!! I need help with this one look at the image

Mathematics

2 answers:

allochka39001 [22]4 years ago

7 0

Answer:

the option C

Step-by-step explanation:

have a great day

Xelga [282]4 years ago

3 0

I believe it’s number 3 because

-4n+8+9n-2 equals 5n+6

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Y = - 2x + 5<br> How to make a table graph using this rule

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3 years ago

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gtnhenbr [62]

Answer:

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Step-by-step explanation:

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3 years ago

1/3+1/4 I really don’t get this so can someone please help me with this problem

Oxana [17]

Answer:

7/12

Step-by-step explanation:

You have to find a common denominator, so you would multiply 3 from the 1/3 by 4 which gets you twelve. And bc you multiplied the 3 you have to multiple the 1 so 1/3 would be 4/12. You would then multiply 4 by 3 and get 12. Then do the same to the one on top. So 1/4 would be 3/12. You then add 3 and 4 and get 7. That’s the numerator, the denominator stays 12. So it would be 7/12

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3 years ago

List multiples to find the lcm 10<br> , 15

morpeh [17]

10-- 10,20,30,40,50,60,70,80,90
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here are a few. The LCM would be 30.
I hope this helps!!

6 0

4 years ago

Read 2 more answers

Give the numerical value of the parameter p in the following binomial distribution scenarioA softball pitcher has a 0.721 probab

Igoryamba

Answer:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19)$

$P(X=16)=(19C16)(0.721)^{16} (1-0.721)^{19-16}=0.112$

$P(X=17)=(19C17)(0.721)^{17} (1-0.721)^{19-17}=0.051$

$P(X=18)=(19C18)(0.721)^{18} (1-0.721)^{19-18}=0.015$

$P(X=19)=(19C19)(0.721)^{19} (1-0.721)^{19-19}=0.002$

And replacing we got:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19) =0.112+0.051+0.015+0.002= 0.1801$

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

For this case our random variable is given by:

$X \sim Binom(n = 19, p = 0.721)$

For this case we want this probability:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19)$

$P(X=16)=(19C16)(0.721)^{16} (1-0.721)^{19-16}=0.112$

$P(X=17)=(19C17)(0.721)^{17} (1-0.721)^{19-17}=0.051$

$P(X=18)=(19C18)(0.721)^{18} (1-0.721)^{19-18}=0.015$

$P(X=19)=(19C19)(0.721)^{19} (1-0.721)^{19-19}=0.002$

And replacing we got:

$P(X>15)= P(X=16)+P(X=17)+P(X=18)+P(X=19) =0.112+0.051+0.015+0.002= 0.1801$

$P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

3 0

4 years ago