A rectangle has a perimeter of 68 inches it’s length is 2 inches less than 3 times the width what is the area of the rectangle
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Answer:
Step-by-step explanation:
We are given that:
Recall that cosine is the ratio of the adjacent side to the hypotenuse. Using the Pythagorean Theorem, solve for the opposite side (we can ignore the negative for now):
And since θ is in QII, sine is positive, and cosine and tangent are both negative.
Sine is the ratio of the opposite side to the hypotenuse. Therefore:
The first thing you need to do is multiply the a and c values. in this problem a is 3 and c is 4. 3x4 is 12. now you need to find the factors of 12 and find a set that add to the b value (-8). -2 + -6 is -8 and -2 x -6 is 12. now you replace -8x with -2x and -6x. now you need to factor by grouping. so first is 3x^2 -6x. you factor out the gcf between the two. in this case it us 3x. so now you have 3x(x-2). now you need to factor the other side of the equation (-2x +4). for this problem you need to factor out a -2, rather then 2, because it needs to be the same as the first half. so you factor out the -2 and get -2(x-2). then you just combine the two so you get (3x-2)(x-2). hope this helped. i also attached a picture of the work. :)
