29) First of all when I write “^2” I mean to the power of 2. Label the bottom line Z or whatever u fancy. Then make 3 equations to solve simultaneously using a^2+b^2=c^2
(1) 14^2+y^2=Z^2
(2) 6^2+y^2=x^2 and (3) x^2+z^2=20^2
The next step is to solve them simultaneously e.g you can rearrange (2) to give you y^2=x^2-6^2 and then input that into (1) to get 14^2+x^2-6^2=Z^2 and again you rearrange (3) to get z^2=20^2-x^2 and input that in and solve for x. Then you will have to repeat that solving for y and only y as the question doesn’t originally ask for z but only for the values of x and y I assume. Using this idea, from glancing at the other questions you should be able to apply this concept to those other questions, if not then make another post outlining any specific questions
Hey there!
Value of x is less than 14 would look like this:
x < 14
Hope this helps you!
God bless ❤️
xXxGolferGirlxXx
Answer:
number 3
Step-by-step explanation:
angleNGL=~angleHGF
<span>There are 10,000 (10*10*10*10) possible sequences. There are 4C3 ways, 4, of having exactly three digits be the same value. The differing digit can be any of the four positions. There are 10P2 ways, 90 (10*9), to choose the digits of the sequence since we have 10 choices for the digit to be repeated, then 9 more options or the differing digit. The product of the combination arrangements and permutation selection, 4*90, shows there are 360 sequences with three of the same digit. Thus the probability is 360/10,000 or 0.036 or 3.6%.</span>
