Share

The distance between the library and town hall is 735 ft the actual distance is 612 ft what is the percent error. Round your ans

tatyana61 [14]

well, we know the actual distance is 612, however the estimate is 735, is off by 735 - 612 = 123.

now if we take 612 to be the 100%, what is 123 off of it in percentage?

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 612&100\\ 123&x \end{array}\implies \cfrac{612}{123}=\cfrac{100}{x}\implies \cfrac{204}{41}=\cfrac{100}{x}\implies 204x=4100 \\\\\\ x = \cfrac{4100}{204}\implies x = \cfrac{1025}{51}\implies x \approx 20.098$

5 0

3 years ago

What is the percent of change if 90 is decreased to 82

Sedbober [7]

Answer: - 8.89%

I am going to explain you in detail ir order to help you to be able to do this kind of problems by yourself.

The definition of percent change, %, is:

          change
% = ---------------- * 100
        base value

The base value is from where you start or the value for which you want to asses the variation.

So, in this case the base value is 90 (starting value).

The change is final value - initial value = 82 - 90 = - 8. The negative sign means that the value decreased.

So, following the formula you get:

         82 - 90                - 8
% = ----------- * 100 = -------- * 100 = - 8.89
            90                     90

Answer: the percent of change is - 8.89 %, meaning that the value decreased 8.89%.

4 0

3 years ago

Read 2 more answers

A sine function had an amplitude of 3, period of 6pi, horizontal shift of 3pi/2, & vertical shift of -1.

Simora [160]

Answer: $\bold{y=\dfrac{1}{2}}$

<u>Step-by-step explanation:</u>

f(x) = A sin (Bx - C) + D

amplitude = |A|
period = $\dfrac{2\pi}{B}$
phase shift = $\dfrac{C}{B}$
vertical shift = D

amplitude of 3 is given so 3 = |A| → A = ± 3, since it is stated that this is a positive function, then A = 3

period of 6π is given so $6\pi=\dfrac{2\pi}{B}\quad \rightarrow \quad B=\dfrac{2\pi}{6\pi}\quad \rightarrow \quad B=\dfrac{1}{3}$

$\text{phase shift is given as}\ \dfrac{3\pi}{2}\ \text{so}\ \dfrac{3\pi}{2}=\dfrac{C}{\frac{1}{3}}\quad \rightarrow\quad \dfrac{(\frac{1}{3})3\pi}{2}=C\quad \rightarrow\quad \dfrac{\pi}{2}=C$