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3 years ago

I will give brainliest plzz

Mathematics

2 answers:

Verdich [7]3 years ago

8 0

Answer:

Need to see the questions lol

natka813 [3]3 years ago

4 0

Answer:

Where's the Questions? Dude

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If the perimeter fence is 250 and the width is 70,what is the length of the fence? (Based on me other question)

Scilla [17]

I believe the length of the fence is 640. (Don't count on my answer, it may not be right).

7 0

4 years ago

What is the probability of getting a sandwich without muenster cheese?

vredina [299]

Answer:

Sorry, I need more information. What's the rest of the question?

3 0

3 years ago

The product of two integers is eighty,their quotient is five.Write both integers in numerical order and separated by a comma,no

Goryan [66]

SOLUTION

Let the two integers be x and y.

Now, the product of x and y, is 80, that is

$\begin{gathered} x\times y=80 \\ xy=80\ldots\ldots\text{.equation 1} \end{gathered}$

The quotient of x and y is 5, that is

$\begin{gathered} x\div y=5 \\ \frac{x}{y}=5\ldots\ldots\ldots\ldots\text{.}\mathrm{}\text{equation 2} \end{gathered}$

From equation 2, make x, the subject, we have

$\begin{gathered} \frac{x}{y}=5 \\ \text{cross multiplying } \\ 5\times y=x \\ x=5y \end{gathered}$

Now substitute the x for 5y into equation 1, we have

$\begin{gathered} xy=80 \\ 5y\times y=80 \\ 5y^2=80 \\ \text{dividing by 5} \\ y^2=\frac{80}{5} \\ y^2=16 \\ \text{take square root of both sides } \\ \sqrt[]{y^2}=\sqrt[]{16} \\ \text{square cancels root} \\ y=4 \end{gathered}$

Now substitute y for 4 into any of the equations.

Let us use equation 1 again, we have

$\begin{gathered} xy=80 \\ x\times4=80 \\ 4x=80 \\ x=\frac{80}{4} \\ x=20 \end{gathered}$

Hence the answer is 4, 20

4 0

1 year ago

Multiply a trinomial and a binomial (2x-5)(-3x2+4x-7)

fiasKO [112]

Answer:

-6x3+23x2-34x-35

Step-by-step explanation:

5 0

3 years ago

Expand

ddd [48]

Answer:

The working of expressions is shown below.

Step-by-step explanation:

We are given the following information:

a) Expand

$3(x+4)\\3\times x + 3\times 4\\3x + 12$

b) Expand and simplify

$4(x+5)-2(x-3)\\=(4x + 20) -(2x-6)\\=( 4x-2x) + (20 + 6)\\= 2x + 26\\=2(x +13)$

c) Expand

$(x+2)(x+7)\\=x\times x + x\times 7 + 2\times x + 2\times 7\\= x^2 + 7x + 2x + 14\\=x^2 + 9x +14$

d) Factorize fully

$12x-18\\=6(2x-3)$

3 0

3 years ago

Read 2 more answers