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Lyrx [107]
3 years ago
10

What conditions would be enough to prove that P is the circumcenter of HJK ?

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
4 0

Answer:

Option A and C

Step-by-step explanation:

<u>Explanation for why I choose option A</u> :-

If you look at the triangle, HK has a midpoint of point L, HJ has a midpoint of point M, and KJ has a midpoint of point N. Now if you stretch the lines inside of the triangle, they intersect at point P which is known as the circumcenter of HJK, true.

<u>Explanation</u><u> </u><u>for</u><u> </u><u>why</u><u> </u><u>I</u><u> </u><u>choose</u><u> </u><u>option</u><u> </u><u>C</u> :-

Now let us look at the lines stretch inside of the triangle. There are three lines which are congruent. Those lines are PK, HP, and PJ (they are the big lines inside the triangle) are congruent. Since those three line intersect at point P, it make the statement true that P is the circumcenter of HJK.

  • Why option B is not an answer?

We do not know the third line (PN) measurements to find that if the three lines (PL, PM, and PN) are congruent and equal 90⁰. Since we do not know, it would not prove that they are congruent and P is the circumcenter of HJK.

  • Why option D is not an answer?

Well it says that triangle HJK is an acute triangle which is true, but this doesn't prove that P is the circumcenter of HJK.

I hope this helps, thank you :) !!

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Step-by-step explanation:

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Answer:

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Step 1

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Guys please help me !!!!
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mode = 43

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Akimi4 [234]

Answer:

value of x =

\sqrt{216}

Step-by-step explanation:

here's the solution,

the given triangle is a right angled triangle so, by applying pythagoras theorem,

=》

perpendicular {}^{2}  =  hypotenuse {}^{2}   - base {}^{2}

=》

{x}^{2}  =  {21}^{2}   -  {15}^{2}

=》

{x}^{2}  = 441 - 225

=》

{x}^{2}  = 216

=》

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