Answer:
=
−
7
/1
1 in fraction form
Step-by-step explanation:
STEP 1: Multiply by 1
1
+
1
0
+
2
5
=
1
8
+
1
0
+
2
5
=
1
8 STEP 2: Combine like terms
+
1
0
+
2
5
=
1
8
1
1
+
2
5
=
1
8 STEP 3: Subtract 2
5 from both sides of the equation
11x+25=18
1
1
+
2
5
−
2
5
=
1
8
−
2
5
STEP 4: Simplify by subtracting the numbers
1
1
+
2
5
−
2
5
=
1
8
−
2
5
11x+25−25=18−25
1
1
=
1
8
−
2
5 1
1
= -7
STEP 5: Divide both sides of the equation by the same term 1
1
=
−
7 11x/
11x = −7/
1
1 (set up as a fraction) STEP 6: Cancel terms that are in both the numerator and denominator
= −
7
/1
1 SOLUTION
= −
7
/1
1
Theory:
The standard form of set-builder notation is <span>
{ x | “x satisfies a condition” } </span>
This set-builder notation can be read as “the set
of all x such that x (satisfies the condition)”.
For example, { x | x > 0 } is
equivalent to “the set of all x such that x is greater than 0”.
Solution:
In the problem, there are 2 conditions that must
be satisfied:
<span>1st: x must be a real number</span>
In the notation, this is written as “x ε R”.
Where ε means that x is “a member of” and R means “Real number”
<span>2nd: x is greater than or equal to 1</span>
This is written as “x ≥ 1”
Answer:
Combining the 2 conditions into the set-builder
notation:
<span>
X =
{ x | x ε R and x ≥ 1 } </span>
Yes. By all means yes. Its very very possible. In fact it can go in there ten times over.
The answer is C
expand the equation then you will get 3-10x-5=9+3x, simplify you get 13x=-11
Your number is 8 I believe
