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morpeh [17]
2 years ago
8

Escribe el número que corresponda a la escritura polinomica 8x10³+4x10²+0x10¹+9x10⁰​

Mathematics
1 answer:
Molodets [167]2 years ago
7 0

Answer:

8409 es 8×10³ es 8 4×10² es 4 0×10¹ es 4 9×10⁰ es 9

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A survey of 542 consumers reveals that 301 favor the new design for a product. Construct a 90% confidence interval for the true
kodGreya [7K]

Answer:

The 90% confidence interval for the true proportion of all consumers who favor the design is (0.52, 0.59).

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In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 542, \pi = \frac{301}{542} = 0.555

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.555 - 1.645\sqrt{\frac{0.555*0.445}{542}} = 0.52

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.555 + 1.645\sqrt{\frac{0.555*0.445}{542}} = 0.59

The 90% confidence interval for the true proportion of all consumers who favor the design is (0.52, 0.59).

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3 years ago
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