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Vlad [161]
2 years ago
9

There are 12 girls and 16 boys . What is the largest number in each group?

Mathematics
1 answer:
lianna [129]2 years ago
8 0

Answer:

Step-by-step explanation:

The largest number of groups they can be split into and have the same number of boys and girls on each team is 6 groups

Given:

Number of girls = 12

Number of boys = 16

Find the highest common factor of 12 and 16

12 = 1, 2, 4

18 = 1, 2,4

The highest common factor of 12 and 16 is 4

Number of girls in each group = 12/4

= 3 girls

Number of boy in each group = 18/4

= 4.5 boys=5

Therefore, the group can be split into 4 groups to have 3 girls and 5 boys in each group

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(y − 1)(y + 10)(y-6) < 0
Aliun [14]

Solve for y by simplifying both sides of the inequality, then isolating the variable.

Inequality Form:

y<−10 or 1<y<6

Interval Notation:

(−∞,−10)∪(1,6)

7 0
2 years ago
urgent!!!! house has 30 windows. kids playing outside the house 40% of the windows. how many windows are broken?​
svetlana [45]

Answer:

12 windows

Step-by-step explanation:

Number of windows broken = 40% of 30

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3 0
3 years ago
"In the 45°-45°-90° triangle above, r = 10. Find the other two lengths.
Basile [38]

We are given a right triangle that has angles of 45°-45°-90°. This would indicate that the triangle is an isosceles type. We can use some trigonemetric functions to solve for the other legs. We do as follows:

 

sin 45 = p / 10

p = 5√2

 

cos 45 = q /10

q = 5√2

 

<span>Hope this answers the question. Have a nice day.</span>

5 0
3 years ago
QUICK, BRAINLIEST FOR 1ST ANSWER. <br><br>14.5 is incorrect!
ra1l [238]
To get the *percent increase* from week 1 to week 2, we calculate the change in distance from week 1 to week 2 (13.5 - 12.5 = 1 mile) over the week 1 distance (12.5 miles). Doing that, we find that Matthew increased his distance by

1/12.5 = 0.08, or 8%

We’re given that he’ll increase his distance by the same percentage from week 2 to 3, so to find his week 3 distance, we can find 8% of the week 2 distance and add that on. 8% of 13.5 miles is 0.08 x 13.5 = 1.08 miles, so by week 3, he’ll be running 13.5 + 1.08 = 14.58 miles.
4 0
3 years ago
An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h
LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

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a = 2.132 ft

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We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

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Therefore, the pool can hold 65.84 ft³ of water

8 0
3 years ago
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