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kirill115 [55]
2 years ago
10

He northern pike can grow a leangth of abt 1 m. write this length in millimeters and in centimeters

Mathematics
2 answers:
Anna007 [38]2 years ago
8 0

Answer:

1000 millimeter and 100 in centimeters

Step-by-step explanation:

monitta2 years ago
5 0

Answer:

its 1000 millimeters and 100 in centimeters

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The angle of depression from a balloon on a 75ft string to a person on the ground is 36°. How high is the balloon?
Rainbow [258]

Answer:

Step-by-step explanation:

sin36=h/75

h=75sin36

h=44.08ft

5 0
2 years ago
hich statement best describes the domain and range of p(x) = 6–x and q(x) = 6x? p(x) and q(x) have the same domain and the same
Sati [7]

Answer:

p(x) and q(x) have the same domain and the same range.

Step-by-step explanation:

p(x) = 6-x and

q(x) = 6x

First of all, let us have a look at the definition of domain and range.

Domain of a function y =f(x) is the set of input value i.e. the value of x for which the function f(x) is defined.

Range of a function y =f(x) is the set of output value i.e. the value of y or f(x) for the values of x in the domain.

Now, let us consider the given functions one by one:

p(x) = 6-x

Let us sketch the graph of given function.

Please find attached graph.

There are no values of x for which p(x) is not defined so domain is All real numbers.

So, domain is (-\infty, \infty) or x\in R

Its range is also All Real Numbers

So, Range is (-\infty, \infty) or x\in R

q(x) = 6x

Let us sketch the graph of given function.

Please find attached graph.

There are no values of x for which q(x) is not defined so domain is All real numbers.

So, domain is (-\infty, \infty) or x\in R

Its range is also All Real Numbers

So, Range is (-\infty, \infty) or x\in R

Hence, the correct answer is:

p(x) and q(x) have the same domain and the same range.

4 0
3 years ago
an object that weighs 1 pound on earth weighs 1.19 pounds on neptune suppose a dog weighs 9 pounds on earth how much would the s
grigory [225]
9x1.19=10.71

This means the dog weighs 10.71 pounds, hope this helps
8 0
2 years ago
2x + 5y = 10 <br><br> i need the slope and y-intercept
ankoles [38]
Y intercept is found by having the x value equal 0 (and vise versus for x intercept) so 5y=10 or simplified y=2
Then you have to find the x intercept (2x=10 and or x=5) then it’s just run over rise (2/5)
3 0
2 years ago
Read 2 more answers
Find the measure of the exterior angle. *
MatroZZZ [7]

Step-by-step explanation:

✧ \underline{ \underline{ \large{ \tt{S \: O \: L \: U \: T \: I \: O \: N}}} }:

  • Set up an equation and solve for x :

⋆ \large{ \bf{(4x + 9) \degree = 2x \degree + (3x - 12) \degree}} [ Exterior angle is always equal to the sum of two non - adjacent interior angles ]

~Remove the unnecessary brackets

⟶ \large{ \bf{4x \degree + 9 \degree = 2x \degree + 3x \degree - 12 \degree}}

~Add the like terms : 2x ° & 3x°

⟶ \large{ \bf{4x \degree + 9 \degree = 5x \degree - 12 \degree}}

~Move 4x to right hand side and change it's sign

~Similarly move 12 to left hand side and change it's sign

⟶ \large{ \bf{9 \degree + 12 \degree = 5x  \degree - 4x \degree}}

⟶ \large{ \bf{21 \degree = x \degree}}

⟶ { \large{ \bf{x  = 21 \degree}}}

  • Now , Substituting the value of x in (4x+9)° [ Exterior angle ]

⤿ \large{ \bf{4 \times 21 \degree + 9 \degree}} =  \boxed{93 \degree}

☥ \boxed{ \boxed{ \large{ \tt{Our \: Final \: Answer :  \boxed{ \underline { \tt{93\degree}}}}}}}

Hope I helped ! ツ

Have a wonderful day / night ! ♡

❅ Let me know if you have any questions regarding my answer! ❅

☞ \underline{ \underline{ \mathfrak{Carry \: On \: Learning}}} !! ✎

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

6 0
3 years ago
Read 2 more answers
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