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2 years ago

13

Humidity refers to a number of indexes used to quantify the amount of water vapor in a parcel of air (held at a consent temperat

ure and pressure).
a. True
b. False

1 answer:

SCORPION-xisa [38]2 years ago

7 0

Answer:

True.

Explanation:

Humidity is the amount of water molecules present in the air at that particular temperature and pressure. As the temperature increases, the air has the ability to hold more water molecules which increases the humidity in the air. The relative humidity is dependent on air temperature. If the water vapor content remains the same and the temperature decreases, the relative humidity increases in the air.

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Is Mesoamerica the same thing as Central America?

serg [7]

Mesoamerica is different from <span>Central America.
</span>Mesoamerica<span> is referring to a region up to the North of Mexico. In the South-West, it also covers the nowadays states of Belize.
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2 years ago

If is parallel to , which statement must be true?

Brilliant_brown [7]

Answer:

they will never cross

Explanation:

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3 years ago

Read 2 more answers

Maps that focus on main ideas are known as what

steposvetlana [31]

What is there any options ? <span>

</span>

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2 years ago

What is the value of X6? <br><br> Show the solution.

wariber [46]

Answer : The value of $x_6$ is $\sqrt{7}$ .

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of $x_1$ .

Using Pythagoras theorem in triangle 1 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_1)^2=(1)^2+(1)^2$

$x_1=\sqrt{(1)^2+(1)^2}$

$x_1=\sqrt{2}$

Now we have to calculate the value of $x_2$ .

Using Pythagoras theorem in triangle 2 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_2)^2=(1)^2+(X_1)^2$

$(x_2)^2=(1)^2+(\sqrt{2})^2$

$x_2=\sqrt{(1)^2+(\sqrt{2})^2}$

$x_2=\sqrt{3}$

Now we have to calculate the value of $x_3$ .

Using Pythagoras theorem in triangle 3 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_3)^2=(1)^2+(X_2)^2$

$(x_3)^2=(1)^2+(\sqrt{3})^2$

$x_3=\sqrt{(1)^2+(\sqrt{3})^2}$

$x_3=\sqrt{4}$

Now we have to calculate the value of $x_4$ .

Using Pythagoras theorem in triangle 4 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_4)^2=(1)^2+(X_3)^2$

$(x_4)^2=(1)^2+(\sqrt{4})^2$

$x_4=\sqrt{(1)^2+(\sqrt{4})^2}$

$x_4=\sqrt{5}$

Now we have to calculate the value of $x_5$ .

Using Pythagoras theorem in triangle 5 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_5)^2=(1)^2+(X_4)^2$

$(x_5)^2=(1)^2+(\sqrt{5})^2$

$x_5=\sqrt{(1)^2+(\sqrt{5})^2}$

$x_5=\sqrt{6}$

Now we have to calculate the value of $x_6$ .

Using Pythagoras theorem in triangle 6 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_6)^2=(1)^2+(X_5)^2$

$(x_6)^2=(1)^2+(\sqrt{6})^2$

$x_6=\sqrt{(1)^2+(\sqrt{6})^2}$

$x_6=\sqrt{7}$

Therefore, the value of $x_6$ is $\sqrt{7}$ .

5 0

2 years ago

2 1.7.3 Quiz: Intersecting Lines and Proofs

olasank [31]

Answer:

C. <ISN and <TSW

D. <TSN and <ISW

Explanation:

When two straight lines intersect each other, the two pairs of the opposite angles formed are called vertical angles.

In the figure given, we have two straight lines, NW and IT, which crosses each other. They form two pairs of opposite angles. They are:

<ISN and <TSW;

<TSN and <ISW.

These pairs of angles formed are vertical angles.

5 0

2 years ago