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3 years ago

A^2-2(a+b)-b^2 plz can anyone solve this factorization

2 answers:

7 0

$\tt\displaystyle\ \star a^2-b^2=(a-b)(a+b)\star\\\\ a^2-2(a+b)-b^2=a^2-b^2-2(a+b)=\\\\\underline{(a+b)}(a-b)-2\underline{(a+b)}=\boxed{(a+b)(a-b-2)}$

Reptile [31]3 years ago

6 0

Step-by-step explanation:

Hope it helps If u have any confusion regarding this kindly inform me , i will try my best to answer

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Find the product: ( x-1/x ) ( x+1/x ) ( x2+1/x2 ) ( x4+1/x4 )

erma4kov [3.2K]

Use the difference of 2 squares (a - b)(a + b) = a^2 - b^2:-

(x - 1/x)(x + 1/x) = x^2 - (1/x)^2

= x^2 - 1/x^2

(x ^2 - 1/x^2)(x^2 + 1 /x^2)

= x^4 - 1/x^4

(x^4 - 1/x^4)(x^4 + 1/x^4)

= x^8 - 1 /x^8 Answer

3 0

3 years ago

0/1

pychu [463]

Answer:

68.8 sq. inches.

Step-by-step explanation:

The triangular surfaces have sides 2 in by 3 in by 4 in.

So, half perimeter, s = $\frac{2 + 3 + 4}{2} = 4.5$

So, the area of the triangular face is $\sqrt{s(s - 4)(s - 2)(s - 3)} = \sqrt{4.5 \times 0.5 \times 2.5 \times 1.5} = 2.9$ sq. inches.

Now, the total surface area of the right triangular prism will be (2.9 × 2) + 7(2 + 3 + 4) = 68.8 sq. inches. (Answer)

4 0

3 years ago

If the difference of two numbers is 43 and the sum of the numbers is 13, what<br> are the numbers?

meriva

Answer:

Numbers are 28 and -15

Step-by-step explanation:

Mark first number X, and second number Y, then:

x-y=43

and

x+y=13

We get system of two equations. Solve it by add both them together:

x-y+x+y=43+13

2x=56

x=28 we get first number

x+y=13

28+y=13

y=13-28

y=-15

4 0

4 years ago

Which of the following is the y-intercept of the line with the equation 2y=6x+4

algol [13]

It is y = 3x + 2, which means the y-intercept is 2. :)

8 0

4 years ago

Algebra applications: find the value of x and y

Inga [223]

Answer : The value of x and y is 8 and 10 respectively.

Step-by-step explanation :

As we known that if two parallel lines are cut by a transversal line then consecutive interior angles are supplementary.

From the given figure we conclude that:

$5x-y+150=180$ ...........(1)

$5x-y=180-150$

$5x-y=30$ ............(2)

$5x+y+130=180$ ...........(3)

$5x+y=180-130$

$5x+y=50$ ...........(4)

Now we adding equation 2 and 4, we get the value of x.

$5x-y+5x+y=30+50$

$10x=80$

$x=8$

Now we are putting the value of x in 4, we get the value of y.

$5x+y=50$

$5(8)+y=50$

$y=50-40$

$y=10$

Therefore, the value of x and y is 8 and 10 respectively.

3 0

3 years ago

A^2-2(a+b)-b^2 plz can anyone solve this factorization​

A^2-2(a+b)-b^2 plz can anyone solve this factorization