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3 years ago

A^2-2(a+b)-b^2 plz can anyone solve this factorization

2 answers:

7 0

$\tt\displaystyle\ \star a^2-b^2=(a-b)(a+b)\star\\\\ a^2-2(a+b)-b^2=a^2-b^2-2(a+b)=\\\\\underline{(a+b)}(a-b)-2\underline{(a+b)}=\boxed{(a+b)(a-b-2)}$

Reptile [31]3 years ago

6 0

Step-by-step explanation:

Hope it helps If u have any confusion regarding this kindly inform me , i will try my best to answer

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Tell me what to put in each group.

erastova [34]

Answer:

{-6 , 7 , 1} {9 , -3 , -4} {5 , -8 , 4} --- 2, 2, 1

Step-by-step explanation:

Number 1: {-6 , 7 , 1} {9 , -3 , -4} {5 , -8 , 4} --- 2, 2, 1

Number 2: {-6 , -3 , 9} {4 , 7 , -8} {5 , 1 , -4} --- 0, 3, 2

Number 2: {-4 , 5 , 1} {7 , 4 , -8} {-6 , -3 , 9} --- 2, 3, 0

4 0

3 years ago

Choose the answer that makes the sentence true.

yaroslaw [1]

Some intergers are natural numbers.

Natural numbers: 1,2,3,4,5

Integers can be positive or negative numbers. So, some of them are natural numbers.

I hope this helps!
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7 0

4 years ago

Pre image ABCD was dilated to produce image A’B’C’D why is the scale factor from the pre image? Enter your answer in the box as

shepuryov [24]

The scale factor of the dilation from ABCD to A′B′C′D′ is 3.

Step-by-step explanation:

Step 1:

In the pre-image ABCD, the length of one of the sides is given as 14 units.

For the other shape A′B′C′D′, the same side as the previous shape is given as 8 units.

Step 2:

To determine the scale factor, we divide the measurement after scaling by the same measurement before scaling.

In this case, it is the given length of the sides CD and C′D′.

So the scale factor = $\frac{C^{1} D^{1} }{CD} = \frac{8}{14} = \frac{4}{7} .$

So the shape ABCD is dilated by a scale factor of $\frac{4}{7}$ to produce the shape A′B′C′D′.

7 0

4 years ago

Jenny bought 4.35kg of

gayaneshka [121]

Answer:

0.15

Step-by-step explanation:

0.35x12=4.2 and there is 4.35 total kgs

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4 years ago

One positive integer is 2 less than another. the product of the two integers is 24. what are the integers?

ehidna [41]

Answer:

The numbers are 6 and 4

Step-by-step explanation:

Let x = integer

The second is x-2

Product of x*(x-2) is 24

x(x-2) = 24

Distribute

x^2 -2x =24

Subtract 24 from each side

x^2 -2x -24 =24-24

x^2 -2x-24 =0

Factor

What two number multiply together to give 24 and add to -2

-6*4= -24

-6+4 = -2

(x-6) (x+4) =0

Using the zero product property

x-6 =0 x+4 = 0

x=6 x=-4

The question states the number is positive

x=6

The second number is x-2 = 4

The numbers are 6 and 4

8 0

4 years ago

A^2-2(a+b)-b^2 plz can anyone solve this factorization​

A^2-2(a+b)-b^2 plz can anyone solve this factorization