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2 years ago

Can you please help me with #7&8 thanks in advance

Mathematics

1 answer:

Ilya [14]2 years ago

3 0

(3/5)(1/2)

Let B = fraction of the bulletin board
for Homeroom 101

B = (3/5)(1/2)

B = 3/10

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Find the missing side. Round to the nearest tenth.

AnnZ [28]

Answer:

B. 29.5

Step-by-step explanation:

Cos=A/H

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x=12/cos66

4 0

2 years ago

The average mass of a certain type of microorganism is 2.4x10^-6 grams. What is the approximate total mass, in grams, of 5x10^3

Solnce55 [7]

I would go with answer b

6 0

3 years ago

FIRST TO ANSWER GET BRAINLEST.

Lostsunrise [7]

Answer:

I believe the answer is B sorry if I'm wrong

3 0

2 years ago

Hi, teacher I was absent these days and I didn’t understand anything about this lesson and I need help this is not count as a te

motikmotik

Given:

There are given that the cos function:

$cos210^{\circ}=-\frac{\sqrt{3}}{2}$

Explanation:

To find the value, first, we need to use the half-angle formula:

So,

From the half-angle formula:

$cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+cos\theta}{2}}$

Then,

Since 105 degrees is the 2nd quadrant so cosine is negative

Then,

By the formula:

$\begin{gathered} cos(105^{\circ})=cos(\frac{210^{\circ}}{2}) \\ =-\sqrt{\frac{1+cos(210)}{2}} \end{gathered}$

Then,

Put the value of cos210 degrees into the above function:

So,

$\begin{gathered} cos(105^{\circ})=-\sqrt{\frac{1+cos(210)}{2}} \\ cos(105^{\operatorname{\circ}})=-\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}} \\ cos(105^{\circ})=-\sqrt{\frac{2-\sqrt{3}}{4}} \\ cos(105^{\circ})=-\frac{\sqrt{2-\sqrt{3}}}{2} \end{gathered}$

Final answer:

Hence, the value of the cos(105) is shown below:

$cos(105^{\operatorname{\circ}})=-\frac{\sqrt{2-\sqrt{3}}}{2}$

4 0

10 months ago

*25 points*

maxonik [38]

Answer:

Step-by-step explanation:

root the 216 as it is a cube

:edge *edge *edge =volume

Since all edges are the same, just root it

7 0

2 years ago

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