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TEA [102]
3 years ago
10

Can you please help me with #7&8 thanks in advance

Mathematics
1 answer:
Ilya [14]3 years ago
3 0
(3/5)(1/2)

Let B = fraction of the bulletin board
for Homeroom 101

B = (3/5)(1/2)

B = 3/10

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20 POINTS!!
Whitepunk [10]
Congruent means they are the same size 

To prove the two triangles are congruent you would need to know the length of at least two of the sides. If two sides were not known you would need to know the length of one side and at least one of the unknown angles.
3 0
3 years ago
The number of miles Ford trucks can go on one tank of gas is normally distributed with a mean of 350 miles and a standard deviat
kati45 [8]

Answer:

The probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.

Step-by-step explanation:

Let <em>X</em> = the number of miles Ford trucks can go on one tank of gas.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 350 miles and standard deviation, <em>σ</em> = 10 miles.

If the Ford truck runs out of gas before it has gone 325 miles it implies that the truck has traveled less than 325 miles.

Compute the value of P (X < 325) as follows:

P(X

Thus, the probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.

7 0
3 years ago
Please need help fast. Look at the picture.<br><br> Please explain.
Zigmanuir [339]
The answer is 17

This is because 1 + 2 must equal 180 as they are in a straight line.
So 4x + 2 + 110 = 180
Take away 110 from both sides
4x + 2 = 70
Take away 2 from both sides to get 4x = 68. Finally, divide both sides by 4 to get x = 17
7 0
3 years ago
1. Juan bought a pair of shoes costing P923.00 and a tie costing P275.00. He gave the seller P2, 000.00. How much change did he
EleoNora [17]
2000.00-923.00-275.00=802.00
4 0
3 years ago
In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>​
Lemur [1.5K]

In both cases,

AB^2=AD^2

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

(4x+7)^2=(6x-3)^2

16x^2+56x+49=36x^2-36x+9

20x^2-92x-40=0

5x^2-23x-10=0

(5x+2)(x-5)=0\implies\boxed{x=5}

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

(4x^2-18x-10)^2=(x^2+x+4)^2

16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16

15x^4-146x^3+235x^2+352x+84=0

(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}

(again, omit the solutions that would give a negative length for either AB or AD)

7 0
3 years ago
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