Try glucose (C6H1206) and water (H2O)?
Answer:
<h2>Factors = (3x - 1) (2x - 1)</h2><h2>values :- x = 1/3 , 1/2</h2>
Step-by-step explanation:
= > 6x^2 + 1 = 5x
• Bring it in the standard form,
= > 6x^2 - 5x + 1 = 0
= > 6x^2 - (3 + 2)x + 1 = 0
= > 6x^2 - 3x - 2x + 1 = 0
• Take out common
= > 3x (2x - 1) - 1 (2x - 1) = 0
= > (3x - 1) (2x - 1) = 0...factors
= > x = 1/3 and 1/2... values of x
<h2>Hope it helps you!! </h2>
Answer:
your answer would be at 11 and 1
Step-by-step explanation:
Answer
Find out the what is the best estimate of the number of liters Ajay's car used .
To prove
As given
Ajay's car used 314 gallons of gas on a trip to the beach.
Assume 1 gallon = 3.8 liters
Than
The number of liters Ajay's car used = 314 × 3.8
= 1193.2 litres
Therefore 1193.2 litres Ajay's car used .
Answer:
13620000
Step-by-step explanation:
