Answer:
the answer is c h2=k2=120%
Step-by-step explanation:
Answer:
$5.63
Step-by-step explanation:
Each bag of bananas is $5.63.
If you divide $28.15 by 5 you get $5.63.
Answer:
Cost to construct the road = 775000 rupees
Step-by-step explanation:
Square field has a side = 150 m
Area of the field = (Side)²
= (150)²
= 22500 m²
Length of the park with road around the field = 150 + 2×(width of the road)
= 150 + (2×5)
= 160 m
Similarly, width of the park with road around the field = 160 m
Area of the park with road = (Side)²
= (160)²
= 25600 m²
Area of road = Area of the park with road - Area of the park
= 25600 - 22500
= 3100 m²
Since, cost of constructing the road = 250 rupees per square meter
Cost to construct the road with the given area = 250 × 3100
= 775000 rupees
Answer:
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
Step-by-step explanation:
Previous concepts
The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

Solution to the problem
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.