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matrenka [14]
3 years ago
7

The diagonal of a TV is 26 inches long. Assuming that this diagonal forms a

Mathematics
1 answer:
shtirl [24]3 years ago
6 0

Answer:

180

Step-by-step explanation:

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I've literally asked this question 5 times lol. Can someone please help me?
Tju [1.3M]
I think i know the answer to that question. just wait for a sec.
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3 years ago
Read 2 more answers
Zach only wants to plant a group of ten flowers in each box is there any way that Zach could plant all 53 flowers using only box
Sveta_85 [38]

Answer:

5.3

Step-by-step explanation:

first u have to get ur numbers then divide 53 by 10

4 0
3 years ago
Answer: 6/2(1+2)=.<br><br><br> explain:
Tcecarenko [31]

Answer:

9

Step-by-step explanation:

6/2(1+2)

6/2(3)

3(3)

9

I hope this helped! If so, please mark brainliest!

8 0
3 years ago
Find the coordinates of the midpoint of a segment with the given endpoints. *
serg [7]

Step-by-step explanation:

Given points are (-2,5) and (3,-17)

to find midpoint, use this formula

( x1+x2/2 , y1+y2/2)

where points are a(x1,y1) and b(x2,y2)

coming to the question,

midpoint is :

[ (-2-3)/2 , (5-17)/2 ]

[ -5/2 , -12/2 ]

[ -2.5 , -6 ]

OPTION A IS CORRECT

8 0
3 years ago
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Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
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