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3 years ago

The table shows data from a school exercise program. If Malinda jogs at the target rate, how far will she travel?

Mathematics

1 answer:

3241004551 [841]3 years ago

5 0

There is no table!!!! Please put a table the next time!!!!

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Multiple choice math question.

Marrrta [24]

Y=x. I hope that this helped! Good luck! :)

4 0

3 years ago

Read 2 more answers

Choose the true statement about the graph of x-1 ≤ 2.

frosja888 [35]

Answer:

circle on 1 and all numbers to the right shaded closed circle on 1 and all numbers to the left shaded

Step-by-step explanation:

4 0

3 years ago

find the coordinates of p so that p partitions segment ab in the part to whole ratio of 1 to 4 with a(-5,4) and b(7,-4)

scoray [572]

Answer:

$p(x,y) = (-2.6 ,2.4)$

Step-by-step explanation:

Given

a(-5,4) and b(7,-4)

Required

Partition P

Given that the segment ab is divided into ratio;

The coordinates of point p can be calculated using ratio formula given below

$p(x,y) = (\frac{mx_2 + nx_1}{m+n} ,\frac{my_2 + ny_1}{m+n})$

Where m and n are the ratio; m = 1 and n = 4

$(x_1, y_1) = (-5,4); \\(x_2, y_2) = (7,-4)$

So,

$p(x,y) = (\frac{mx_2 + nx_1}{m+n} ,\frac{my_2 + ny_1}{m+n})$ becomes

$p(x,y) = (\frac{1 *7 + 4 * -5}{1+4} ,\frac{1 * -4 + 4 * 4}{1+4})$

$p(x,y) = (\frac{7 + -20}{5} ,\frac{-4 + 16}{5})$

$p(x,y) = (\frac{-13}{5} ,\frac{12}{5})$

$p(x,y) = (-2.6 ,2.4)$

Hence, the coordinates of p are (-2.6,2.4)

3 0

4 years ago

What is the exact area and arc length of these sectors? Please helppp

Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = $\frac{90}{360} \times \pi \times 12^2 = 36\pi$

2. Area of sector 2 = $\frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi$

3. Area of sector 3 = $\frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi$

4. Area of sector 4 = $\frac{270}{360} \times \pi \times 6^2 = 27 \pi$

5. Arc length of sector 1 = $\frac{90}{360} \times 2 \times \pi \times 12 = 6\pi$

6. Arc length of sector 2 = $\frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi$

7. Arc length of sector 3 = $\frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi$

8. Arc length of sector 4 = $\frac{270}{360} \times 2 \times \pi \times 6 = 9\pi$

4 0

3 years ago

Yard

Lana71 [14]

Answer:

Step-by-step explanation:

3 0

3 years ago