If <em>f(x)</em> = 1/<em>x</em> - 2, then the average rate of change between <em>x</em> = 4 and <em>x</em> = 8 is
(<em>f</em> (8) - <em>f</em> (4)) / (8 - 4) = ((1/8 - 2) - (1/4 - 2)) / 4 = -1/16
If you meant <em>f(x)</em> = 1/(<em>x</em> - 2), then it would be
(<em>f</em> (8) - <em>f</em> (4)) / (8 - 4) = (1/(8 - 2) - 1/(4 - 2)) / 4 = (1/6 - 1/2) / 4 = -1/12
<em>Make sure to check which one is the correct function!</em>
1)Rewrite the table:
70, 49, 34.3, 24.01, 11.807 {The original size of the wound =70}
2) write the quotient of each number by the number before & notice the value:
49/70= 0.7
34.3/49 = 0.7
24.01/34.3 =0.7
16.0807/24.01 = 0.67 ≈0.7
You notice this is a geometric progression with r 0.7
The last term in a GP =ar^⁽ⁿ⁻¹⁾
3) Domain and Range of this function:
Last term = a₁.rⁿ⁻¹. let last term be y==> f(n) = y =70(0.7)ⁿ⁻¹
or f(n) = y = 70(0.7)ⁿ / 0.7==> f(n) = [(0.7)ⁿ ]/ 100.
This is a decreasing exponential function where the coefficient
raised to n is < 1.
The domain is for all n>= 0.
When n→∞, f(n)→0; For n=0==>f(n) =70. So the range of f(n) is:<=70
We can find out two point on the line (0,2)and(4,1)
The slope =(2-1)/(0-4)=-1/4
Answer:
-2
Step-by-step explanation:
go back 3 into the negatives
