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shutvik [7]
3 years ago
14

Solve the simultaneous equations 2x + 5y = 16 - 2x + 3y = 8

Mathematics
1 answer:
anygoal [31]3 years ago
4 0

Answer:

2x+y= -2, x + 2y = 2

x+y=3 , 2x-8y = 19

6x^2+3y^2=12 , x +y = 2

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-7w+8 (w+1)=w-7<br> Please show work
kvv77 [185]
Hello there.^••^

−7w+8(w+1)=w−7
w+8=w−7
w+8−w=w−7−w8=−7
8−8=−7−80=−15
No solutions.
6 0
3 years ago
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60203 round to nearest ten
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60200 since the three rounds down
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What is the magnitude of force required to accelerate a car
Drupady [299]

Answer:

8.71 x 10^3N - C

Step-by-step explanation:

Force = mass x acceleration

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3 years ago
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A school cafeteria has 30 boxes of Wheaty Squares cereal and 20 boxes of Mighty O's
Basile [38]

Answer:

50e=t

Step-by-step explanation:

Wheaty Squares = w

Mighty O's = m

ounces in each box = e

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5 0
3 years ago
Use the intermediate value theorem to find the value of c such that f(c) = M. f(x) = x^2 - x + 1 text( on ) [1,8]; M = 21 c =
DanielleElmas [232]

Answer:

c = 5

Step-by-step explanation:

Given

f(c) = M

f(x) = x^2 - x + 1

Interval: [1,8]

M = 21

Required

Find c using Intermediate Value theorem

First, check if the value of M is within the given range:

f(x) = x^2 - x + 1

f(1) = 1^2 - 1 + 1

f(1) = 1

f(x) = 8^2 - 8 + 1

f(x) = 57

1 \le M \le 57

1 \le 21 \le 57

M is within range.

Solving further:

We have:

f(c) = f(x) = M

f(x) = 21

Substitute 21 for f(x) in f(x) = x^2 - x + 1

21 = x^2 - x + 1

Express as quadratic function

x^2 - x + 1 - 21  = 0

x^2 - x - 20  = 0

Expand

x^2 + 4x - 5x - 20

x(x+4)-5(x+4)=0

(x - 5)(x+4) = 0

x - 5 = 0 or x + 4= 0

x = 5 or x = -4

The value of x = -4 is outside the Interval: [1,8]

So:

x = 5

f(c) = f(x) = M

f(c) = f(5) = 21

By comparison:

c = 5

4 0
3 years ago
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