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3 years ago

Given p(x) = x+7/3 if p(x) = 13, find x.

Mathematics

1 answer:

Shtirlitz [24]3 years ago

3 0

Answer:

x = $\frac{32}{3}$

Step-by-step explanation:

We know that p(x) = 13. Thus, substitute 13 for the "p(x)" in the equation. Then, isolate x by subtracting both sides by $\frac{7}{3}$ :

$p(x) = x + \frac{7}{3}\\13 = x + \frac{7}{3} \\13 - \frac{7}{3} = x \\\frac{39}{3}- \frac{7}{3} = x \\\frac{32}{3} = x$

Thus, x = $\frac{32}{3}$ .

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Five more than three times a number is 197. find the mlnumber

insens350 [35]

Answer:

Step-by-step explanation:

If the number is x we have the equation:-

3x + 5 = 197

Subtract 5 from both sides:-

3x = 192

x = 192/3

x = 64

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3 years ago

A box of candies has 14 pieces in total. If 2 of the pieces are strawberry flavored what is the ratio of the other flavors to th

creativ13 [48]

Answer:

12:2 or 6:1

Step-by-step explanation:

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3 years ago

Find the distance between the given points: (2, -2) and (-4, 7)

sasho [114]

Answer:

$3\sqrt{13}$

Step-by-step explanation:

Hi there!

We want to find the distance between the points (2, -2) and (-4, 7).

To do that, we can use the distance formula.

The distance formula is given as $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are points

We have everything needed to find the distance, but let's label the values of the points to avoid any confusion

$x_1=2\\y_1=-2\\x_2=-4\\y_2=7$

Now substitute those values into the formula and solve

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\sqrt{(-4-2)^2+(7--2)^2}$

Simplify

$\sqrt{(-4-2)^2+(7+2)^2}$

$\sqrt{(-6)^2+(9)^2}$

Square the numbers under the radical

$\sqrt{36+81}$

Add the numbers under the radical together

$\sqrt{117}$

Simplify the square root

$3\sqrt{13}$

Hope this helps!

6 0

3 years ago

What is the equation for 8r=4r -16

bagirrra123 [75]

Answer:

r= -4

Step-by-step explanation:

subtract 4 from both sides of the equation:

4r=16

simplify:

r= -4

6 0

3 years ago

On a coordinate plane, parallelogram H I J K is shown. Point H is at (negative 2, 2), point I is at (4, 3), point J is at (4, ne

nasty-shy [4]

HIJK is a parallelogram because the midpoint of both diagonals is

(1 , 0), which means the diagonals bisect each other

Step-by-step explanation:

If (x , y) is the mid-point of a segment whose end points are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ then,

$x=\frac{x_{1}+x_{2}}{2}$

$y=\frac{y_{1}+y_{2}}{2}$

In a parallelogram, its diagonals intersect each other at their mid-points

that means its diagonals bisect each other

∵ HIJK is a quadrilateral

∵ HJ and IK are its diagonals

∵ H = (-2 , 2)

∵ J = (4 , -2)

- Find the mid point of HJ

∵ $M_{HJ}=(\frac{-2+4}{2},\frac{2+-2}{2})$

∴ $M_{HJ}=(\frac{2}{2},\frac{0}{2})$

∴ $M_{HJ}=(1,0)$

∴ The mid-point of HJ is (1 , 0)

∵ I = (4 , 3)

∵ K = (-2 , -3)

- Find the mid point of IK

∵ $M_{IK}=(\frac{4+-2}{2},\frac{3+-3}{2})$

∴ $M_{IK}=(\frac{2}{2},\frac{0}{2})$

∴ $M_{IK}=(1,0)$

∴ The mid-point of IK is (1 , 0)

∵ The mid-points of HJ and IK are equal

∴ HJ and IK bisects each other

∴ HIJK is a parallelogram because its diagonals bisect each other

HIJK is a parallelogram because the midpoint of both diagonals is

(1 , 0), which means the diagonals bisect each other

Learn more:

You can learn more about parallelogram in brainly.com/question/6779145

#LearnwithBrainly

6 0

3 years ago

Read 2 more answers