Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer: The answer is your bad, you shouldnt be "answering" questions with " sorry i need points"
Answer
180
if your feeling nice can you give me a brainlest :)
Answer: [0,3]
The line is going up from left to right between 0 and 3 on the x-axis. We use a closed bracket because it is a open circle.
Answer:
-480
Step-by-step explanation:
If f varies directly as g, and inversely as h, then we can write the variation equation:
, where k is the constant of variation.
If g=56 when h=-2 and f=-7, then we substitute these values into the formula to find the value of k.
The equation now becomes:
if f=10 and h=-12, then;
The correct answer is B.
